If you can give me more information on this I could help you a bit more respond.
Answer:
<em>Option C. is the correct option.</em>
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Step-by-step explanation:
<em>Clara found the product of (3 - 6y²) and (y² + 2) and she did it as below</em>
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<em>(3 - 6y²)(y² + 2) = 3(y²) + (-6y²)×2 = 3y² - 12y² = -9y²</em>
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<em>She did the step wrong as highlighted above. She did not use the distributive property correctly.</em>
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<em>Now we will do it in a correct way.</em>
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<em>(3 - 6y²)(y²+2) = 3(y² + 2) - 6y²(y² + 2)</em>
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<em>= 3y^{2}+6-6y^{4}-12y^{2}=-6y^{4}-9y^{2}+6</em>
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<em>Therefore Option C. is the correct answer.</em>
<em>Hope it helps:)</em>
(5,-3) , (-19,-3) , (-7,9), (-7,-15)
Answer:
2
Step-by-step explanation:
To find <em>a</em> we need to first isolate it. There is a 5 on the left side along with the -3a that has to be moved.
To do this, we can subtract 5 from both sides of the equation using the subtraction property of equality.
-3a + 5 - 5 = - 1 - 5
-3a = -6
Now that the a term is isolated, the next step is to remove the coefficient.
Let's use the division property of equality and divide both sides of the equation by -3.
-3a/-3 = -6/-3
a = 2