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Komok [63]
3 years ago
10

14 points to brainliest

Mathematics
2 answers:
jeka943 years ago
7 0
Its AAS=Angle angle side 
Ludmilka [50]3 years ago
5 0
ABC and DBC is Side Angle Side
You might be interested in
The polynomial p(x)=1−2x2−3x3+4x has what order?<br><br> a. 4<br> b. 2<br> c. 3<br> d. 1
VLD [36.1K]

Answer:

3

Step-by-step explanation:

Given the polynomial : p(x)=1−2x2−3x3+4x

Rearranging : p(x) = -3x³ - 2x² + 4x + 1

Looking at the polynomial Given, we can see that it is a univariate polynomial, that is it has only one variable which is x. Thus for polynomials of this sort, the order of the polynomial is the highest exponent occurring in the polynomial equation. Therefore, the order of the polynomial above is 3, because the highest power of the function is 3.

This means that those with 4 as their highest exponent are of order 4 and those with highest exponent as 2 are of order 2.

3 0
3 years ago
Justine bought a pair of boots for $76.68 and paid 13% sales tax. What was the price of these boots including tax?
MArishka [77]

Answer: $86.65

Step-by-step explanation:

First, find how much Justine paid in tax. To do this, first convert 13% to a decimal by dividing by 100. This gets a tax rate of 0.13. Now, multiply the price of the boots by the tax rate. 76.68*0.13 = 9.9684. Round to the nearest cent to get $9.97.

Now, add the amount paid in tax to the price of the boots. 76.68+9.97 = $86.65.

4 0
2 years ago
I need help with this math question (Img included)
Mandarinka [93]
Answer: C. 5
Because (x^(2/3))(x^(3/3))=x^(5/3)
5 0
2 years ago
Determine whether the equation defines y as a function of x.<br> x+y=9 and x^2+y^2=1 and x=y^2
Murrr4er [49]

Answer:

Function: x+y=9

Not Function: x^2+y^2=1    and     x=y^2

Step-by-step explanation:

Given

x+y=9

x^2+y^2=1

x=y^2

Required

Determine if y is a function of x

Solving x+y=9

x+y=9

Make y the subject of formula

y = 9 - x

<em>Hence; y is a function of x</em>

Solving x^2+y^2=1

x^2+y^2=1

Subtract x² from both sides

y^2=1 - x^2

Square root of both sides

y =\± \sqrt{1 - x^2}

This implies that

y =\sqrt{1 - x^2}     or     y =-\sqrt{1 - x^2}

<em>Because </em>y<em> can be any of those two expressions, it is not a function.</em>

Solving x=y^2

x=y^2

Reorder

y^2 = x

Take square roots

y = \±\sqrt{x}

This implies that

y = \sqrt{x}      or        y = -\sqrt{x}

<em>Because </em>y<em> can be any of those two expressions, it is not a function.</em>

4 0
3 years ago
Evaluate 10 to the 7th
Olenka [21]

Ya came to the right place! Its 10,000,000 fam

5 0
3 years ago
Read 2 more answers
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