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inna [77]
3 years ago
10

Why does a layer 3 device perform the anding process on a destination ip address and subnet mask?

Computers and Technology
1 answer:
mafiozo [28]3 years ago
8 0
To get the network number and node number of the destination machine. The subnet mask is usually called the NETwork MASK, so anding it with the address gives you the network number. Using the not logical operator on the netmask then protects the node bits in a second and operation.

address & netmask = network number
address & not( netmask ) = node number

The not operator essentially just flips the bits of it's argument.
You might be interested in
In C++ please (read the image below for instructions)
FromTheMoon [43]

Using the knowledge in computational language in C code  it is possible to write a code that  print the month name along with their rainfall inches. Then we have to calculate the total rainfall.

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using </em><em>namespace </em><em>std;</em>

<em />

<em>// function to print the rainfall of each month</em>

<em>void rainfallStatistics(string month[], double rainfall[]){</em>

<em>    </em>

<em>    double sum = 0; // variable to store the total sum of rainfall</em>

<em>    string maxMonth = month[0]; // variable to return month with maximum rainfall</em>

<em>    double </em><em>maxRainfall </em><em>= INT_MIN; // variable to store the maximum rainfall</em>

<em>    </em>

<em>    // running the loop till the last month</em>

<em>    for(int i=0; i<12; i++){</em>

<em>        </em>

<em>        // printing the month and rainfall</em>

<em>        cout<< month[i] << "           " << fixed << setprecision(2) << rainfall[i] << " inches" << endl;</em>

<em>        </em>

<em>        // storing the sum</em>

<em>        sum = sum + rainfall[i];</em>

<em>        </em>

<em>        // checking the month with highest rainfall</em>

<em>        if(rainfall[i] > </em><em>maxRainfall</em><em>){</em>

<em>            </em>

<em>            maxRainfall = rainfall[i];</em>

<em>            maxMonth = month[i];</em>

<em>        }</em>

<em>    }</em>

<em>    </em>

<em>    // calculating the average of the rainfall</em>

<em>    double average = sum / double(12);</em>

<em>    </em>

<em>    cout << endl;</em>

<em>    cout << "Total for the year " << sum << " inches" << endl;</em>

<em>    cout << "Average rainfall per month " << average << " inches" << endl;</em>

<em>    cout << "Month with the greatest rainfall was " << maxMonth << " with rainfall of " << </em><em>maxRainfall </em><em><< " inches" << endl;</em>

<em>    </em>

<em>}</em>

<em>// driver program</em>

<em>int main()</em>

<em>{</em>

<em>    // array to store the nonth name</em>

<em>    string month[12] = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};</em>

<em>    </em>

<em>    // array to store the rainfall</em>

<em>    double rainfall1[12] = { 4.50, 4.25, 3.26, 1.35, 0.80, 0.20, 0.10, 0.00, 0.40, 1.20, 2.96, 4.71 };</em>

<em>    double rainfall2[12] = { 3.50, 1.25, 7.26, 8.35, 2.80, 0.00, 1.10, 4.00, 9.40, 2.20, 3.96, 4.71 };</em>

<em>    </em>

<em>    cout << "Hayward Statistics" << endl;</em>

<em>    cout << endl;</em>

<em>    cout<< "Month" << "         " << "Rainfall" << endl;</em>

<em>    </em>

<em>    // calling the function for Hayward</em>

<em>    </em><em>rainfallStatistics</em><em>(month, rainfall1);</em>

<em>    cout << endl;</em>

<em>    cout << endl;</em>

<em>    </em>

<em>    cout << "Houston Statistics" << endl;</em>

<em>    cout << endl;</em>

<em>    cout<< "Month" << "         " << "Rainfall" << endl;</em>

<em>    </em>

<em>    // calling the function for Houston</em>

<em>    rainfallStatistics(month, rainfall2);</em>

<em>    </em>

<em>    return 0;</em>

<em>}</em>

See more about c code at brainly.com/question/19705654

#SPJ1

8 0
1 year ago
The inability of BAE Automated Systems to create an automated baggage handling system led to a significant delay in the opening
Sergeu [11.5K]

Answer:

True

Explanation:

Airport was truly opened outside the city of Denver, because of the faults in BAE automated system.

6 0
3 years ago
Write a program that takes a point (x,y) from theuser and find where does the point lies. The pointcan
agasfer [191]

Answer:

C++ Program .

#include<bits/stdc++.h>

using namespace std;

int main()

{

int x,y;//declaring two variables x and y.

string s;//declaring string s..

cout<<"enter x and y"<<endl;

cin>>x>>y;//taking input of x and y..

if(x>=0 &&y>=0) //condition for 1st quadrant..

cout<<"the point lies in 1st Quadrant"<<endl;

else if(x<=0 &&y>=0)//condition for 2nd quadrant..

cout<<"the point lies in 2nd Quadrant"<<endl;

else if(x>=0 &&y<=0)//condition for 3rd quadrant..

cout<<"the point lies in 3rd Quadrant"<<endl;

else //else it is in  4th quadrant..

cout<<"the point lies in 4th Quadrant"<<endl;

cout<<"enter n to terminate the program"<<endl;

while(cin>>s)//if the user has not entered n the program will not terminate..

{

   if(s=="n")

   {

       cout<<"the program is terminated"<<endl;

       exit(0);

   }

   cout<<"you have not entered n please enter n to terminate the program<<endl;

}

}

Explanation:

The above written program is for telling the point lies in which quadrant.I am first declaring two variables x and y.Then after that taking input of x and y after that checking in which quadrant the point lies.

Taking input of the string s declared earlier for program termination the program will keep running until the user enters n.

4 0
3 years ago
EASY AND I GIVE BRAINLIEST!!! What is a good jeopardy question about operating systems?
madam [21]

 ______ is used in operating system to separate mechanism from policy
<span><span>A. Single level implementation</span><span>B. Two level implementation</span><span>C. Multi level implementation</span><span>D. None</span></span>
3 0
3 years ago
The term “frivolous” implies that the author
tiny-mole [99]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
believes that the average individual does not need a smart phone 
<span>firivolous mean not serious, light, unimportant.</span>

3 0
3 years ago
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