Ask question

Ask question

All categories

3 years ago

12

Y=1/8x+c is the family of solutions of the differential equation y'=-8y^2, find the solution that satisfies the initial conditio

n y(0)=3

1 answer:

meriva3 years ago

4 0

Y(0) = 3 <=> (1/8)·0 + c = 3 <=> c = 3 <=> y = (1/8)·x + 3;

You might be interested in

Find the area of this figure.

umka2103 [35]

Rectangle

l = 7.2 - 1.7 = 5.5 ft b = 3.4 ft

Semicircle

r = 1.7 ft

Shaded region = area of rectangle + area of semicircle

= l x b + πr²/2

= 5.5 x 3.4 + 3.14 x 1.7 x 1.7 x 1/2

= 18.7 + 4.5373

= 23.2373 ft²

6 0

3 years ago

Which is the graph of g(x)?

faust18 [17]

Answer: A because its always A

Step-by-step explanation:

6 0

2 years ago

Another representation, in polar coordinates, of the point (3, 5pi/4) is ( ___, pi/4)

VladimirAG [237]

The answer is (-3, pi/4). I just took the quiz

3 0

3 years ago

Read 2 more answers

Simplify. square root (108 x^5 y^6)

sveta [45]

$\bf \sqrt{108x^5y^6}\qquad 
\begin{cases}
108=2\cdot 2\cdot 3\cdot 3\cdot 3\\
\qquad 2^2\cdot 3^2\cdot 3\\
\qquad (2\cdot 3)^2\cdot 3\\
\qquad 6^2\cdot 3\\
x^5=x^{4+1}\\
\qquad x^4\cdot x^1\\
\qquad x^{2\cdot 2}\cdot x\\
\qquad (x^2)^2\cdot x\\
y^6=y^{3\cdot 2}\\
\qquad (y^3)^2
\end{cases}\implies \sqrt{6^2\cdot 3\cdot (x^2)^2\cdot x\cdot (y^3)^2}
\\\\\\
6x^2y^3\sqrt{3x}$

3 0

3 years ago

After m months, the height of a plant is 10+3m millimeters. How tall is the plant after eight months? Three years?

Oksanka [162]

Why not start out by writing a linear relationship for the plant height?

h(m) = 10 + 3m, where h is the height in mm and m is the time in years, starting from zero (0).

After 8 months, the plant height is h(8) = 10 mm + 3(8) mm, or 34 mm.

After 3 years (36 months), the plant ht. is h(36) = 118 mm.

4 0

3 years ago