. In the commercial production of sugar (sucrose), the product crystals are washed and centrifuged to partial dryness. The cryst
als are then sent through a rotary dryer where they are contacted with a hot stream of air that reduces the moisture content from 1:0 wt% to 0:1 wt%. The ratio of wet sugar to inlet air fed to the dryer is 3.3 kg wet sugar/kg inlet air. The inlet air contains 1.5 mole% water. (a) Draw and label the flowchart and do the degree-of-freedom analysis
1 answer:
Answer:
x4,w = 0.03wt%
= 0.03/18 / 0.03/18 + 0.97/ 28.84
= 0.047mol%
Step-by-step explanation:
Let m1 = 100kg
Given:
m1 / m3 = 3.3kg
So, m3 = 3.3 x 100 = 30.30 kg
Degree of freedom analysis:
Xw,3 = 0.015 (18) / 0.015(18) + 0.985(28.84)
= 0.0094%wt
(1 – 0.01)(100kg) = (1- 0.001)m2
m2 = (1 – 0.01)(100kg) / 0.999
m2 = 99.1kg
(100kg)0.01 + 0.0094(30.3kg) = (99.1kg)0.001 + x4,w
(1-0.0094)(30.3) = m4 ( 1-x4,w)
m4 = 30.95kg
x4,w = 0.03wt%
= 0.03/18 / 0.03/18 + 0.97/ 28.84
= 0.047mol%
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<u><em>note:</em></u>
<u><em>please find the attached solution</em></u>
