A parabola y=1/2x^2-4x+21 can you help me find the vertex form of this parabola please and thank you :)

1 answer:

3 0

Ok
First factor out the first 2 terms as follows:-

y = 1/2(x^2 - 8x) + 21

Now complete the square on x^2 - 8x:-

y = 1/2[ (x - 4)^2 - 16] + 21

y = 1/2(x - 4)^2 - 8 + 21

y = 1/2(x - 4)^2 + 13 Answer

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You intend to estimate a population mean with a confidence interval. You believe the population to have a normal distribution. Y

Luda [366]

Answer:

T = 4.541

Step-by-step explanation:

We don't have the standard deviation for the population, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.98}{2} = 0.99$ . So we have T = 4.541