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nika2105 [10]
2 years ago
9

Pls tell me which to pick (a,b,c,or d)

Mathematics
1 answer:
Elodia [21]2 years ago
4 0

Answer:

B (Y, N, N)

Step-by-step explanation:

a) y = 1/3x, so each value satisfies it. This is true.

b) If "a" is "Y" then b has to be no

c) 1 * 11 = 11

2 * 2 = 22

3 * 5 = 15

The last equation does not follow the rules for the previous two equations, so it is no.

Thus, the answer is B (Y, N, N)

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What is the approximate solution to the equation 3t=29 ? 0.3263 3.0650 3.3672 9.6667
Norma-Jean [14]

Answer:

9.6667

Step-by-step explanation:

3t=29

Divide each side by 3

3t/3 = 29/3

t = 29/3

Three goes into 29  nine times  (3*9 = 27 ) with 2 left over

t =  9 2/3

We know 1/3 = .3 repeating

so 2/3  = .6 repeating


t = 9 .6 repeating

7 0
2 years ago
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What is 5/6 divided by-2/3
liraira [26]

Answer: -5/4


Step-by-step explanation:

Apply the fraction rule: a/-b = -a/b

-5/6/2/3

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Divide fractions: a/b/c/d = a x d/ b x c

-5 x 3 / 6 x 2

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Multiply the numbers: 6 x 2 = 12

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Multiply the numbers: 5 x 3 = 15

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Cancel the common factor.3

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Sorry if this is a little confusing but your answer to the question is ( -5/4 )

3 0
3 years ago
What is the volume of the triangular prism?
Rasek [7]

Answer:

The answer is 480 cubic inches

Step-by-step explanation:

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3 0
3 years ago
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dusya [7]
B I think I am unsure
5 0
3 years ago
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What is the equation of the following line? Be sure to scroll down first to see all answer options.
Harrizon [31]
<h3><u>Answer:</u></h3>

Hence, the equation of line is:

y= -6x

<h3><u>Step-by-step explanation:</u></h3>

Clearly from the graph we could see that the line passes through the point (0,0) and (-1/2,3).

Also we know that the equation of a line passing through (a,b) and (c,d) is given as:

y-b=\dfrac{d-b}{c-a}\times (x-a)

Here we have:

(a,b)=(0,0) and (c,d)=(-1/2,3)

Hence, the equation of line is:

y-0=\dfrac{3-0}{-\dfrac{1}{2}-0}\times (x-0)\\\\\\\\y=\dfrac{3}{\dfrac{-1}{2}}\times x\\\\y=3\times (-2)\times x\\\\y=-6x

Hence, the equation of line is:

y= -6x

6 0
3 years ago
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