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nika2105 [10]
2 years ago
9

Pls tell me which to pick (a,b,c,or d)

Mathematics
1 answer:
Elodia [21]2 years ago
4 0

Answer:

B (Y, N, N)

Step-by-step explanation:

a) y = 1/3x, so each value satisfies it. This is true.

b) If "a" is "Y" then b has to be no

c) 1 * 11 = 11

2 * 2 = 22

3 * 5 = 15

The last equation does not follow the rules for the previous two equations, so it is no.

Thus, the answer is B (Y, N, N)

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A ball is thrown into the air with an upward velocity of 80ft/s. Its height H in feet after T seconds id given by the function H
pashok25 [27]
1. The function H= -16T^2+80T+5 is a parabola of the form a x^{2} +bx+c, so to find the maximum height of the ball, we are going to find the y-coordinate of the vertex of the parabola. To find the y-coordinate of the vertex we are going to evaluate the function at the point \frac{-b}{2a}.
From our function we can infer that b=80 and a=-16, so the point \frac{-b}{2a} [/tex] will be \frac{-80}{-2(16)} = \frac{5}{2}. Lets evaluate the function at that point:
h=-16t^2+80t+5
h=-16( \frac{5}{2} )^2+80( \frac{5}{2} )+5
h=105

We can conclude that the ball reaches a maximum height of 105 feet.

2. Since we now know that the maximum height the ball reaches is 105 feet, we are going to replace h with 105 in our function, then we are going to solve for t to find how long the ball takes to reach its maximum height:
h=-16t^2+80t+5
105=-16t^{2}+80t+5
-16t^2+80t-100=0
-4(4t^{2}+20t-25)=0
4(2t-5)^2=0
2t-5=0
t= \frac{5}{2}
t=2.5

We can conclude that the ball reaches its maximum height in 2.5 seconds.

3. Just like before, we are going to replace h with 5 in our original function, then we are going to solve for t to find how long will take for the ball to be caught 5 feet off the ground:
h=-16t^2+80t+5
5=-16t^2+80t+5
-16t^{2}+80t=0
-16t(t-5)=0
t-5=0
t=5

We can conclude that it takes 5 seconds for the ball to be caught 5 feet off the ground.
5 0
3 years ago
Determine whether the Mean Value Theorem applies to the function f(x)=2x^1/5 on the interval [-32, 32]
Anettt [7]

Answer

given,

f(x) = 2 x^{1/5}

interval = [-32, 32]        

differentiating the given equation

f'(x) = \dfrac{d}{dx}(2 x^{1/5})

f'(x) = \dfrac{2}{5x^{4/5}}

hence, the above solution is not defined at x = 0

and x = 0 lie in the given interval i.e. [-32, 32]

so, at x = 0 the function is not differentiable.

Hence, mean value theorem does not apply to the given function.

5 0
3 years ago
If you have $.25 on your debit card do you have enough To buy a volleyball glove. Yes or no
jekas [21]

Answer:

No

Step-by-step explanation:

8 0
3 years ago
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OFind the missingangle measures.B.m 41 =9058°A4m 42 =31089Em 3 =o
Anastaziya [24]

step 1

Find the measure of angle 1

REmember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

In the triangle ABC

90+58+<1=180

148+<1=180

<1=180-148

<1=32 degrees

step 2

Find the measure of angle 2

we know that

<2=<1 -----> bt vertical angles

so

<2=32 degrees

step 3

Find the measure of angle 3

REmember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

In the triangle CDE

32+108+<3=180

140+<3=180

<3=180-140

<3=40 degrees

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1 year ago
Which of the following could be the shape of the cross section of the cone?
kondaur [170]
Triangle hope this helps
7 0
3 years ago
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