Question

What is the inverse of the logarithmic function f(x) = log2x?

Answer 1

Is it supposed to say log[base2]x? if thats the case then f^-1(x)=2^x (aka 2 with an exponent of x)

Answer 2

Answer:

Inverse function, $f^{-1}=2^x$

Step-by-step explanation:

We are given a function $f(x)=\log_2x$

We need to find the inverse of f(x)

Step 1: Set f(x)=y

$y=\log_2x$

Step 2: Switch x and y

$x=\log_2y$

Step 3: Solve for y (isolate y)

$y=2^x$              $\because \log_ab=x\Rightarrow b=a^x$

Inverse of function $f(x)\rightarrow f^{-1}(x)=2^x$