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saul85 [17]
3 years ago
14

The homeowner installs an electrically heated mirror into the shower room.When a person has a shower, the heated mirrors does no

t become misty but stays clear.
Why does the mirror stay clear?
Physics
2 answers:
UkoKoshka [18]3 years ago
8 0
When you have a warm shower, you create steam. So when the warm steam flows in the air and starts to be in contact with a cold surface, it condenses causing a mist to form on the cold surface. The heated mirror is warm so, when, the steam is in contact with the mirror condensation is prevented. Therefore, the mirror stays clear.
Scrat [10]3 years ago
8 0
Cause the only reason a mirror becomes misty when you take a shower is because the steam from the water rises and then condenses on the cold surface of the mirror cause it cools down the steam back to it's origional form of water. But if you had a heated mirror the steam wouldn't condense back to water when it touched the mirror so the mirror stays clear:)    
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A student solving a physics problem for the range of a projectile has obtained the expression
Alika [10]

Answer:

The range of the projectile is 66.7 meters.

Explanation:

The range of a projectile is given by the following expression as :

R=\dfrac{v_o^2\ sin2\theta}{g}..............(1)

v_o=37.2\ m/s

\theta=14.1^{\circ}

g=9.8\ m/s^2

The range can be calculated using equation (1). Putting the values of all parameters we get :

R=\dfrac{(37.2)^2\ sin2(14.1)}{9.8}

R = 66.7 meters

So, the range of the projectile is 66.7 meters. Hence, this is the required solution.

6 0
3 years ago
Can someone help me? Idk why I can't understand this
olya-2409 [2.1K]
It's been a while since I've studied this, but my answers would be:

13. 5730 years. The half-life of a substance is the amount of time it takes for half of it to decay, and, according to the graph, half of the substance remained at 5730 years.

14. 10740 years. According to the graph, only 25% of the carbon remained after 10740 years.

15. 15 atoms. According to the graph, only 12.5% of the carbon remained after 16110 years. 12.5% of 120 atoms is 15 atoms.

16. 1600 atoms. According to the graph, if a sample of carbon is 10740 years old, only 25% of it remains. To find the original amount, multiply the current amount by (100% / 25%), which equals 4. So, 4. 400 atoms * 4 = 1600 atoms is the original amount.
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4 years ago
What is her velocity
fenix001 [56]
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7 0
3 years ago
A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provid
Sergeeva-Olga [200]

Answer:

8.37*10^5 rpm

Explanation:

Given that rotational kinetic energy = 4.66*10^9J

Mass of the fly wheel (m) = 19.7 kg

Radius of the fly wheel (r) = 0.351 m

Moment of inertia (I) = \frac{1}{2} mr ^2

Rotational K.E is illustrated as (K.E)_{rt} = \frac{1}{2} I \omega^2

\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }

\omega = \sqrt{\frac{2(KE)_{rt}}{1/2 mr^2} }

\omega = \sqrt{\frac{4(K.E)_{rt}}{mr^2} }

\omega = \sqrt{\frac{4*4.66*10^9J}{19.7kg*(0.351)^2} }

\omega = 87636.04

\omega = 8.76*10^4 rad/s

Since 1 rpm = \frac{2 \pi}{60}  rad/s

\omega = 8.76*10^4(\frac{60}{2 \pi})

\omega = 836518.38

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3 0
3 years ago
Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a neutron star.
Andrews [41]

Answer:

The question is incomplete however this kind of questions about determinate the angular speed and taking a reference of days rotating the first star.

w=0.11312 rad/s

Explanation:

The situation is about a two star the question is incomplete, miss the time rotate one star so we assume the first star rotated once in 30 days so:

Angular momentum

P_{m}=I*w

The inertia

I=\frac{3}{5}*m*r^2

The momentum must be conserved so

P_{m1}=P_{m2}

I_{1}*w_{1}=I_{2}*w_{2}

\frac{2}{5}*m*r_{1}^2*w_{1}=\frac{2}{5}*m*r_{2}^2*w_{2}

notice don't have to know the mass or use the density however at the end can determinate

w_{2}=\frac{r_{1}*w_{1}}{r_{2}}

Time can determinate the frequency so determinate angular speed of the first star

w_{1}=2\pi*f_{1}

t_{1}=30days*\frac{24hr}{1day}*\frac{60minute}{1hr}*\frac{60s}{1minute}=2592000s

f_{1}=\frac{1}{t_{1}}=\frac{1}{2592000}=3.858x10^-7Hz

w_{1}=2.424x10^{-6}\frac{rad}{s}

w_{2}=\frac{7.0x10^8m}{15x10^3m}*2592000

w_{2}=0.11312 rad/s

4 0
3 years ago
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