The time required by the car to stop is 4.916 sec.
Since the car is moving with the constant deceleration we can apply the first equation of motion to calculate the time required by the car to stop.
The first equation of motion is given as
V=u+at
Here, V=final speed of the car=0 mi/h as the car stops
u =initial speed of the car=55 mi/hr=24.58 m/s
a= acceleartion =-5 m/s^2 (here negative sign indicates for deceleration)
Now applying the values in the first equation
V=u+at
0=24.58-5*t
t=4.916 sec
Therefore the car will stops in 4.916 sec.
Answer:
700 joules
Explanation:
potential energy = m × h × g
( m = mass, h = height, g = acceleration due to gravity )
- P.E = 14 × 5 × 10
- P.E = 700 J
hence, gravitational potential energy of the object is 700J
<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
The net force on a car traveling around a curve is the centripetal force, Fc = m v2 / r, directed toward the center of the curve.
Explanation:LET ME KNOW IF ITS WRONG. HAVE A NICE DAY!!!!!!!!!!
