Please solve fast. I will give Brainleist or whatever it’s called

Hong has been given a list of 6 bands and asked to place a vote. his vote must have the names of his favorite and second favorit

mixas84 [53]

This requires us to find the number of permutations of 6 different bands taken 2 at a time:
$6P2=\frac{6!}{(6-2)!}=30\ different\ votes.$

7 0

3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$

a) Probability that a student has either a Visa card or a Master Card is given by,

$P(V \cup M) = P(V) + P(M) - P(V\cap M)$

$P(V \cup M) = 0.63+ 0.11- 0.03$

$P(V \cup M) =0.74- 0.03$

$P(V \cup M) =0.71$

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if $P(A\cap B)=P(A)P(B)$

For V and M to be independent the condition is satisfied,

$P(V\cap M)=P(V)P(M)$

Substitute the values,

$0.03=0.63\times 0.11$

$0.03\neq 0.0693$

So, V and M are not independent.

6 0

3 years ago

Does anyone know the answer to this?

Alex

Answer:

10.5.

Step-by-step explanation:

By similar triangles:

IJ / 21 = 8 /(8+8) = 1/2

IJ / 21 = 1/2

IJ = 1/2 * 21

= 10.5.

6 0

3 years ago

Why is the product of 9s diagonal?

Nadusha1986 [10]

Answer:

A. With each 9s fact you add another 9, which means you go straight down a row and back one space. This creates a diagonal pattern in the grid.

6 0

3 years ago

here are several types of objects. For each type of object, estimate how many there are in a stack that is 5 feet high. Be prepa

lorasvet [3.4K]

We need to estimate how tall is, on average, one of these object, and then count how many would be in a 5 feet high stack.

For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.

So, if we set the equation

$1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}$