All categories

2 years ago

What scale factor do you use to make A 5mm object 100mm ?

Mathematics

1 answer:

Flauer [41]2 years ago

7 0

Answer:

Utiliza una cifra que pueda ser resultado de dividir 100:5 y eso a su vez nos dará el valor que debe aumentar en la escala

You might be interested in

Suppose

DerKrebs [107]

Answer:

Is this even possible

Step-by-step explanation:

7 0

2 years ago

The lowest point in Death Valley is Badwater at 282 feet below sea level. The highest point in

Finger [1]

Answer:

Step-by-step explanation:

Given

$Badwater = -282ft$

$Telescope\ Peak = 11043ft$

The position of badwater is negated because it is below sea level

The interpretation of the question, is to calculate the distance between the two given points.

This is calculated as:

$Difference = Telescope\ Peak - Badwater$

$Difference = 11043ft - (-282ft)$

Open bracket

$Difference = 11043ft+282ft$

$Difference = 11325ft$

<em>Hence, the distance between both is 11325ft</em>

8 0

2 years ago

At a sale this week, a sofa is being sold for $555. This is a 26% discount from the original price. What is the original price?

vlabodo [156]

Divide 555/.26 & you’ll get your original price

6 0

2 years ago

What is the value of the expression below?

Ghella [55]

Answer:

A. 12

Step-by-step explanation:

use pemdas

4^4=16

20+8=28

28-16=12

4 0

2 years ago

Read 2 more answers

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$