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3 years ago

5

What scale factor do you use to make A 5mm object 100mm ?

1 answer:

Flauer [41]3 years ago

7 0

Answer:

Utiliza una cifra que pueda ser resultado de dividir 100:5 y eso a su vez nos dará el valor que debe aumentar en la escala

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On field day, Danny captured 6 times as many flags as Jon during a game of capture the flag. Together, they captured 14 flags. H

Monica [59]

Answer:

The number of flags captured by Danny was 12

The number of flags captured by Jon was 2

Step-by-step explanation:

Let

x-----> number of flags captured by Danny

y---> number of flags captured by Jon

we know that

$x+y=14$ ------> equation A

$x=6y$ -----> equation B

substitute equation B in equation A and solve for y

$6y+y=14$

$7y=14$

$y=2\ flags$

Find the value of x

$x=6(2)=12\ flags$

therefore

The number of flags captured by Danny was 12

The number of flags captured by Jon was 2

5 0

3 years ago

What is the value of n?<br> (3×n)+4=<br> 32÷2

Reptile [31]

It would be n=4
3x+4=32/2
3x+4=16
-4. -4
3n=12
3. 3
N=4

6 0

3 years ago

Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30

TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

$-7, -3, 1, 5, . . .$

An arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4$

$\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$d=4$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=-7$

as

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=4\left(n-1\right)-7$ ∵ $d=4$

$\mathrm{Arithmetic\:sequence\:sum\:formula:}$

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

$\mathrm{Plug\:in\:the\:values:}$

$n=30,\:\space a_1=-7,\:\spaced=4$

$=30\left(-7+\frac{4\left(30-1\right)}{2}\right)$

$=30\left(58-7\right)$ ∵ $\frac{4\left(30-1\right)}{2}=58$

$=30\cdot \:51$

$=1530$ ∵ $\mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530$

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

$a_n=4\left(n-1\right)-7$

n = 30

$\sum _{n=1}^{30}\:4\left(n-1\right)-7$

$=\sum _{n=1}^{30}4n-11$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n$

$=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11$

as

$\sum _{n=1}^{30}4n=1860$

and

$\sum _{n=1}^{30}11=330$

so

$=1860-330$

$=1530$

7 0

4 years ago

Which of the following points best represent ...

Sedbober [7]

B I think sorry if I’m wrong

4 0

3 years ago

Please help fast

Ber [7]

I believe the answer to your question id they first one and its f(x)=3x-3

5 0

4 years ago