Answer:
4 IS $1
8 IS $2
12 IS $3
16 IS $4
Step-by-step explanation:
On the coordinate plane it would be a number on the top left and point at a bottom number, the top left is the first number and on the bottom is the last number. Hope that helped!
We've hit on a case where a measure of center does not provide all the information spread or variability there is in month-to-month precipitation. based on how busy each month has been in the past, lets managers plan
The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.
In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.
So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:
![P(\text{rolling two 6s}) = P(\text{rolling a 6}) \cdot P(\text{rolling a 6}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}](https://tex.z-dn.net/?f=%20P%28%5Ctext%7Brolling%20two%206s%7D%29%20%3D%20P%28%5Ctext%7Brolling%20a%206%7D%29%20%5Ccdot%20P%28%5Ctext%7Brolling%20a%206%7D%29%20%3D%20%5Cdfrac%7B1%7D%7B6%7D%20%5Ccdot%20%5Cdfrac%7B1%7D%7B6%7D%20%20%3D%20%5Cdfrac%7B1%7D%7B36%7D%20)
Similarly,
![P(\text{rolling two 3s}) = P(\text{rolling a 3}) \cdot P(\text{rolling a 3}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}](https://tex.z-dn.net/?f=%20P%28%5Ctext%7Brolling%20two%203s%7D%29%20%3D%20P%28%5Ctext%7Brolling%20a%203%7D%29%20%5Ccdot%20P%28%5Ctext%7Brolling%20a%203%7D%29%20%3D%20%5Cdfrac%7B1%7D%7B6%7D%20%5Ccdot%20%5Cdfrac%7B1%7D%7B6%7D%20%20%3D%20%5Cdfrac%7B1%7D%7B36%7D%20)
Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:
![P(\text{rolling any ordered couple}) = P(\text{rolling the first number}) \cdot P(\text{rolling the second number}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}](https://tex.z-dn.net/?f=%20P%28%5Ctext%7Brolling%20any%20ordered%20couple%7D%29%20%3D%20P%28%5Ctext%7Brolling%20the%20first%20number%7D%29%20%5Ccdot%20P%28%5Ctext%7Brolling%20the%20second%20number%7D%29%20%3D%20%5Cdfrac%7B1%7D%7B6%7D%20%5Ccdot%20%5Cdfrac%7B1%7D%7B6%7D%20%20%3D%20%5Cdfrac%7B1%7D%7B36%7D%20)