Answer:
3 to 5
Explanation:
The pH scale is from 0 to 14.
Acids have a pH of anything less than 7.
Anything with a pH greater than 7 is considered to be a base.
If a solution has a pH of 7, it is neutral.
3 to 5 is in the range of less than 7, so a solution of an acid can have this pH.
6 to 8 includes less than 7 , 7 and greater than 7, so it is not just in the range of an acid.
9 to 11 and 12 to 14 are both in the range of greater than 7, so they have to be bases.
Therefore, the correct answer is 3 to 5.
Explanation:
George Washington Carver was born enslaved and went on to become one of the most prominent scientists and inventors of his time, as well as a teacher at the Tuskegee Institute. Carver devised over 100 products using one major crop — the peanut — including dyes, plastics and gasoline.
Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K
Explanation :
Formula used :

where,
= change in entropy
= change in enthalpy of fusion = 3.17 kJ/mol
As we know that:

= freezing point temperature = 
Now put all the given values in the above formula, we get:



Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K
Answer:
Explanation:
In the solution of AB , they are split to give ions as follows
AB ⇄ A⁺ + B⁻
Product of concentration of A⁺ and B⁻ in saturated solution of AB is constant .
This is called Ksp
Ksp = [A⁺] [ B⁻]
If product of concentration of A⁺ and B⁻ exceeds Ksp , the equilibrium shifts to the left side and excess ions come out of solution in the form of precipitate. So second option is the answer.