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Mice21 [21]
2 years ago
9

Does water added to a flask containing chlorine gas and solid sodium react in the chemical reaction to make sodium chloride

Chemistry
1 answer:
Jet001 [13]2 years ago
5 0

Answer:

Explanation:

Chemically, we can have a reaction between chlorine gas and solid sodium

This reaction is actually explosive and would produce fine powder of sodium chloride

We have the reaction as follows:

2Na_{(s)}+Cl_{2(g)}\rightarrow2NaCl_{(s)}

Essentally, what we can deduce from here is that we do not need to add water to the flask. Except for the reason that we would want the sodium chloride solid in the solution form, there is absolutely no reason to add water to the flask as the reaction would proceed normally

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The empirical formula for this compound that contain 31.14%sulfur and 68.86%chlorine by mass
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The empirical formula is SCl_2.

The <em>empirical formula</em> (EF) is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the <em>molar ratio </em>of S to Cl.

Assume that you have 100 g of sample.

Then it contains 31.14 g S and 68.86 g Cl.

<em>Step</em> 1. Calculate the <em>moles of each element</em>

Moles of S = 31.14 g S × (1 mol S/(32.06 g S) = 0.971 30 mol S  

Moles of Cl = 68.86 g Cl × (1 mol Cl/35.45 g Cl) = 1.9425 mol Cl

<em>Step 2</em>. Calculate the <em>molar ratio</em> of each element

Divide each number by the smallest number of moles and round off to an integer

S:Cl = 0.971 30: 1.9425 = 1:1.9998 ≈ 1:2

<em>Step 3</em>: Write the <em>empirical formula</em>

EF = SCl_2

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Laughing gas (nitrous oxide, N20) is some-
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A 4.08 g sample of a compound composed of nitrogen and oxygen contains 3.02 g of oxygen. What is the empirical formula
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Answer:

Explanation:

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