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marin [14]
3 years ago
10

A balloon filled with 1.22 L of gas at 286 K is heated until the

Chemistry
1 answer:
TiliK225 [7]3 years ago
4 0

Answer: 670K

Explanation:

Given that,

Original volume of gas V1 = 1.22 L

Original temperature T1 = 286 K

New volume V2 = 2.86 L

New temperature T2 = ?

Since volume and temperature are involved while pressure is constant, apply the formula for Charles law

V1/T1 = V2/T2

1.22 L/286 K = 2.86 L/ T2

Cross multiply

1.22 L x T2 = 286 K x 2.86 L

1.22T2 = 817.96

Divide both sides by 1.22

1.22T2/1.22 = 817.96/1.22

T2 = 670.459 K (Round to the nearest whole number as 670 K)

Thus, the temperature of the gas is 670 Kelvin

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4 0
3 years ago
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2.50 g of Zn is added to 5.00 g of HCl
Debora [2.8K]
Zn+2HCl ----> 2ZnCl2 + H2

For 2.50 g of Zn

Mass per mol = 2.50/molar mass of Zn = 2.50/65.38 = 0.0382 g/mol
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For 2 g of HCl

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What is the normal pH range of a Base?
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2 years ago
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If 20.0 grams of Al is placed into a solution containg
meriva

Answer:

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