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erica [24]
3 years ago
7

If a mountain climber performs 180,000) of work climbing a 200 m cliff, how much force did he use?

Chemistry
1 answer:
ELEN [110]3 years ago
4 0

Answer:

the question is not clear

Explanation:

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What is the difference between heterozygous and homozygous
ExtremeBDS [4]

If an organism is heterozygous, it has one copy of two different alleles. If an organism is homozygous, it has two copies of the same allele.

8 0
3 years ago
You decide you want to carry a boulder home from the beach. It is 20 centimeters on each
e-lub [12.9K]

Answer:

Weight of boulder = 22,400 gram

Explanation:

Given:

Volume = 8,000 cm³

Density = 2.8

Find:

Weight of boulder

Computation:

Weight of boulder = Volume x Density

Weight of boulder = 8,000 x 2.8

Weight of boulder = 22,400 gram

3 0
3 years ago
What element is similar to Baruim
aivan3 [116]

Answer:

calcium ca

Explanation:

We can see here that the only element that is on the same group (column) as Ba (Barium) is Calcium (Ca).

3 0
2 years ago
Read 2 more answers
Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2
erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0
3 years ago
A vessel contains a mixture of gases. The mass of each gas used to make the mixture is known. Which of the following information
faltersainse [42]

Answer: The molar mass of each gas

Explanation:

Mole fraction is the ratio of moles of that component to the total moles of solution. Moles of solute is the ratio of given mass to the molar mass.

\text{Mole fraction of solute}=\frac{\text{Moles of solute}}{\text{Total Moles}}

Suppose if there are three gases A, B and C.

a) \text{Mole fraction of A}=\frac{\text{Moles of A}}{\text{ Moles of (A+B+C)}}

b) \text{Mole fraction of B}=\frac{\text{Moles of B}}{\text{ Moles of (A+B+C)}}

c) \text{Mole fraction of C}=\frac{\text{Moles of C}}{\text{ Moles of (A+B+C)}}

moles of solute =\frac{\text {given mass}}{\text {Molar mass}}

Thus if mass of each gas is known , we must know the molar mass of each gas to know the moles of each gas.

8 0
3 years ago
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