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2 years ago

Two different isotopes of an element have different?

Chemistry

1 answer:

lukranit [14]2 years ago

7 0

The answer is: Different number of neutrons.

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What do cyanobacteria use to produce energy and by what process do they produce energy

andrezito [222]

As they contain, green pigement they can perform "Photosynthesis" and obtains energy from that process

Hope this helps!

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3 years ago

NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Zanzabum

True

Explanation:

It is correct to say that the biosphere includes all of the fish that are in the ocean. Even though the ocean is part of the hydrosphere.

The biosphere includes all life form on earth wherever they may dwell from deep abyss to the high atmosphere.

The different spheres on earth are interacting with one another and they depend on each other.

Just like the earth systems, the spheres of the earth relates with each other. Even the ocean is contained in the geosphere.

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Biodiversity brainly.com/question/10723602

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3 years ago

What can you tell about the location of the Sun from this illustration of the Milky Way? A) It is outside of the Milky Way. B) I

MakcuM [25]

It is within the central bulge

7 0

3 years ago

A student finds that the water's temperature went from 18oC to 38oC. Calculate how many calories are in the peanut.

Norma-Jean [14]

Answer:

567 calories.

Explanation:

There 567 calories in 100 grams of peanut. In 100 grams of peanut, 49 gram is the fat, 26 grams of protein, 16 grams of carbohydrates, Sodium is 18 mg, Potassium is 705 mg. Calcium is present in peanut about 9%, Iron is 25% , Vitamin B-6 is 15% and Magnesium is 42% of their total weight. Oil content is high in the Peanut so this is the reason for high calories in peanut. It is a good source of proteins and potassium.

4 0

3 years ago

How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of

alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

Explanation:

we'll apply the following equation for electric field of a point charge on a spherical conductor

$E = k \frac{q}{r^{2} }$

where E is the electric field

k is a constant of the value 8.99 x 10⁹ Nm²/C²

r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

$E = k \frac{q}{r^{2} }$

q = E x r²

q = 1250 N/C x 0.205m²

8.99 x 10⁹ Nm²/C²

q = 5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

$n = \frac{q}{e}$

n = 5.84 x 10⁻⁹ C

1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

3 0

3 years ago