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Advocard [28]
2 years ago
12

How many moles of iron are there in 55.85g of Fe3O4

Chemistry
1 answer:
soldier1979 [14.2K]2 years ago
8 0

Answer:

• Molecular mass of Iron (III) tetraoxide

\dashrightarrow \: { \tt{(56 \times 3) + (16 \times 4)}} \\  = { \tt{168 + 64}} \\  = { \tt{232\:g}}

[ molar masses: Fe → 56, O → 16 ]

\dashrightarrow \:{ \rm{232 \: g \:  = 1 \: mole}} \\ \\   \dashrightarrow \: { \rm{55.85 \: g = ( \frac{55.85}{232}) \: moles }} \\  \\ \dashrightarrow \:  { \boxed{ \tt{ = 0.24 \: moles}}}

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Nitric acid is produced commercially by the Ostwald process, represented by the following equations. 4 NH3(g) + 5 O2(g) 4 NO(g)
Marrrta [24]

Answer:

The answer to your question is: 1538095.2 kg of NH3

Explanation:

MW HNO3 = 63 kg

MW NO2 = 46 kg

                         3 NO2(g) + H2O(l)--- 2 HNO3(aq) + NO(g)

                            3(46) kg--------------   2(63) kg  

                                  x     ---------------  7600000 kg

           x = 7600000 x 138/126 = 8323809.5 kg og NO2

MW NO = 30            

                         2 NO(g) + O2(g)---2 NO2(g)

                       2(30) ------------------2(46)

                        x        ---------------- 8323809.5 kg  

             x = 8323809.5 x 60/92 = 5428571.4 kg of NO

MW NH3 = 17 kg

                      4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)

                       4(17) -------------------- 4(30)

                         x ----------------------- 5428571.4

x = 5428571.4 x 34 / 120

x = 1538095.2 kg of NH3

4 0
3 years ago
Do elements have DNA?
jeyben [28]
Not most elements have DNA, only five "elements" have DNA. <span>The five "elements" are Carbon, Oxygen, Hydrogen, Nitrogen and Phosphorus. Good luck with your question I hope this is what you were looking for.</span>
6 0
3 years ago
BRAINLIESTTT ASAP!!!! PLEASE HELP ME :)
Elan Coil [88]

Answer:

1s² 2s²2p³  

Explanation:

If the atom has seven electrons, it is Element 7 (nitrogen).

In the Periodic Table, you count the electrons in all the subshells up to

No. 7.

In the first Period, you have filled the 1s level (2 electrons).

In the second Period, you have filled the 2s subshell (2 electrons) and put three electrons in the 2p subshell.

Thus, the electron configuration is

1s² 2s²2p³

Note how the superscripts tell you the number of electrons in each subshell: <em>2 + 2 + 3 = 7</em>.

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