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2 years ago

How many moles of iron are there in 55.85g of Fe3O4

Chemistry

1 answer:

soldier1979 [14.2K]2 years ago

8 0

Answer:

• Molecular mass of Iron (III) tetraoxide

$\dashrightarrow \: { \tt{(56 \times 3) + (16 \times 4)}} \\ = { \tt{168 + 64}} \\ = { \tt{232\:g}}$

[ molar masses: Fe → 56, O → 16 ]

$\dashrightarrow \:{ \rm{232 \: g \: = 1 \: mole}} \\ \\ \dashrightarrow \: { \rm{55.85 \: g = ( \frac{55.85}{232}) \: moles }} \\ \\ \dashrightarrow \: { \boxed{ \tt{ = 0.24 \: moles}}}$

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Answer:

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Step 1: Data given

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Mass of water = moles of water * molar mass of water

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