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Advocard [28]
2 years ago
12

How many moles of iron are there in 55.85g of Fe3O4

Chemistry
1 answer:
soldier1979 [14.2K]2 years ago
8 0

Answer:

• Molecular mass of Iron (III) tetraoxide

\dashrightarrow \: { \tt{(56 \times 3) + (16 \times 4)}} \\  = { \tt{168 + 64}} \\  = { \tt{232\:g}}

[ molar masses: Fe → 56, O → 16 ]

\dashrightarrow \:{ \rm{232 \: g \:  = 1 \: mole}} \\ \\   \dashrightarrow \: { \rm{55.85 \: g = ( \frac{55.85}{232}) \: moles }} \\  \\ \dashrightarrow \:  { \boxed{ \tt{ = 0.24 \: moles}}}

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How do you find concentration from absorbance mg and ml?
sweet-ann [11.9K]
Great question, let me know if you get the anwser!
8 0
3 years ago
How many molecules are in 6.0g of sodium phosphate?
Phantasy [73]

Answer:

2.2 x 10²² molecules.

Explanation:

  • Firstly, we need to calculate the no. of moles in (6.0 g) sodium phosphate:

<em>no. of moles = mass/molar mass </em>= (6.0 g)/(163.94 g/mol) = <em>0.0366 mol.</em>

  • <em>It is known that every mole of a molecule contains Avogadro's number (6.022 x 10²³) of molecules.</em>

<em />

<u><em>using cross multiplication:</em></u>

1.0 mole of sodium phosphate contains → 6.022 x 10²³ molecules.

0.0366 mole of sodium phosphate contains → ??? molecules.

<em>∴ The no. of molecules in  6.0 g of sodium phosphate</em> = (6.022 x 10²³ molecules)(0.0366 mole)/(1.0 mole) = <em>2.2 x 10²² molecules.</em>

3 0
2 years ago
Which coefficient before potassium (K) balances this chemical equation?
miskamm [114]

Answer:

The coefficient before potassium (K) balances this chemical equation is 2.

Explanation:

_K +Cl₂ → 2KCl

K =1 ; Cl =2

K=1 × 2 = 2

Cl = 1 × 2 = 2

2 K +Cl₂ = 2 KCl

5 0
3 years ago
Read 2 more answers
67.4 L of sulfur dioxide (SO2) gas at 0.0C and at 1 atm of pressure is equivalent aren’t to how many moles?
gizmo_the_mogwai [7]

Solution here,

Volume(V)=67.4 L

Pressure(P)=1 atm

Temperature(T)=(0+273)K=273K

Universal gas constant(R)=0.0821 L.atm.mol^-1K^-1

No. of moles(n)=?

Now,

PV=nRT

or, 1×67.4=n×0.0821×273

or, 67.4=22.4n

or, n=67.4/22.4

or, n=3

therefore, required no. of mole is 3.

6 0
3 years ago
What is the concentration of a solution with a volume of 2.5 liters containing 600 grams of calcium phosphate?​
trapecia [35]

Answer:

1.12M

Explanation:

Given parameters:

Volume of solution  = 2.5L

Mass of Calcium phosphate  = 600g

Unknown:

Concentration  = ?

Solution:

Concentration is the number of moles of solute in a particular solution.

Now, we find the number of moles of the calcium phosphate from the given mass;

        Formula of calcium phosphate  = Ca₃PO₄

         molar mass = 3(40) + 31 + 4(16) = 215g/mol  

Number of moles of  Ca₃PO₄  = \frac{600}{215}   = 2.79moles

   Now;

  Concentration  = \frac{Number of moles }{volume }  

 Concentration  = \frac{2.79}{2.5}   = 1.12M

7 0
3 years ago
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