The Evaluating expression √6 +√6+√27-√12 become √3(2√2+ 1) after simplification.
According to the statement
We have given that one evaluating expression which is √6 +√6+√27-√12
And we have to simplify this expression by evaluating it.
So, Given expression is:
√6 +√6+√27-√12
√6 +√6+√(9*3)-√(4*3)
√6 +√6+3√(3)-2√(3)
√6 +√6+√3( 3-2)
After evaluating the expression it become
√6 +√6+√3(1)
√(3*2) +√(3*2) +(1)√3
Take common from above expression then
√3(√2 +√2 ) +√3
√3(2√2) +√3
√3(2√2+ 1)
Now the expression √6 +√6+√27-√12 become √3(2√2+ 1) after simplification.
So, The Evaluating expression √6 +√6+√27-√12 become √3(2√2+ 1) after simplification.
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Question:
Which choice is equivalent to the expression below?
√6 +√6+√27-√12
A. √3(2√2+ 1)
B. 2√3-√21
C. 3√3+√6
D. 5√3
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Step-by-step explanation:
I count four 6s, four 4s and three b.
so, we have
6⁴×4⁴×b³ or (using the same symbols as above)
6⁴.4⁴.b³
Answer:
y = 20, x = 44
Step-by-step explanation:
Answer:
Option 4.
Step-by-step explanation:
By graphing these we see that these triangles are Similar which means that there corresponding angles measure is equal i-e all angles are equal and hence option 4 is the answer
Answer:
Step-by-step explanation:
In ΔABC, we have
The Converse of the basic proportionality theorem states that if a line divides two sides of a triangle in same ratio then the line must be parallel to the third side.
Now, it is given that , this implies that line segment DE divides AB and AC in the same ratio.
Thus, by converse of basic proportionality theorem
line segment DE= line segment BC.
Therefore, if ,then line segment DE is parallel to line segment BC .
