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3 years ago

What are the limit laws???

1 answer:

8 0

In Calculus - limits, there are several limits law, but the most common ones should be the following:

limx-->a [f(x) + g(x)] = L+M
limx-->a [f(x) - g(x)] = L-M
limx-->a f(x)/g(x) = L/M, if M does not equal to 0

Hope this helps!

You might be interested in

34 over w = 40 over 100

antiseptic1488 [7]

34/w = 40/100
40w = 340
340/40 =w
w= 8.5 or 85/ 10

8 0

3 years ago

Order the set of integers from least to greatest 5, -3, -12, 9

Sauron [17]

Answer:

-12, -3, 5, 9

Step-by-step explanation:

ok. So the numbers are 5, -3, -12, and 9.

In these numbers, there are 2 negatives. They are -12 and -3.

In negatives, the bigger the number is, the number is smaller.

So we first put

-12, -3 as our 2 first. Then the other ones are 5 and 9.

and you obviously know that 5 is less than 9. try it out. 9-5 =4 which is positive

So then you put 5, 9

And our full answer is

-12, -3, 5, 9

7 0

3 years ago

Read 2 more answers

A number is selected randomly from the integer from 10to30 what is the probability of picking a multiple of 4or5

arlik [135]

Answer:

$\frac{3}{7}$

Step-by-step explanation:

Start by finding how many integers there are from 10-30...

30-10+1=20+1=21

Note we have to add 1 since it is inclusive.

Now, let's find how many multiples of 4 or 5 there are from 10-30...

4*3=12

4*4=16

4*5=20

4*6=24

4*7=28

5*2=10

5*3=15

5*4=20

5*5=25

5*6=30

5+5-1=9

Note we have to subtract 1 since 20 is counted twice.

The probability would be...

$\frac{Multiples\ of\ four\ and\ five\ from\ 10-30}{Amount\ of\ integers\ between\ 10-30}=\frac{9}{21}=\frac{3}{7}$

6 0

2 years ago

Wich expression represent the sum of 59 and x

KIM [24]

I don't see the answers, but it would most likely be 59 + x.

7 0

4 years ago

It takes 300 newtons of force and a distance of 20 meters for a moving car to come to stop. How much work is a one n the cart?

IceJOKER [234]

Work done on cart
:

W
=
6000

J
Kinetic energy of cart
:

E
K
=
6000

J
Explanation:
Work done
W
is defined as the product of force
F
and distance
s
:
⇒
W
=
F
⋅
s
Let's substitute the values of
F
and
s
into the equation:
⇒
W
=
300

N

⋅
20

m
⇒
W
=
300

kg

⋅

m s
−
2

⋅
20

m
⇒
W
=
300
⋅
20

kg

⋅

m
2

s
−
2
⇒
W
=
6000

kg

⋅

m
2

s
−
2
∴
W
=
6000

J
The gain in kinetic energy
E
K
is the same amount as the work done moving the cart:
∴
E
K
=
6000

7 0

3 years ago