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charle [14.2K]
3 years ago
6

What are the limit laws???

Mathematics
1 answer:
Whitepunk [10]3 years ago
8 0
In Calculus - limits, there are several limits law, but the most common ones should be the following:

limx-->a [f(x) + g(x)] = L+M
limx-->a [f(x) - g(x)] = L-M
limx-->a f(x)/g(x) = L/M, if M does not equal to 0

Hope this helps!
You might be interested in
Refer to the triangle below. If a = 4 and b = 6, solve for c. show work Also, give the unsimplified radical form answer and then
9966 [12]

Look at the image below where I labeled the sides

To solve this you must use Pythagorean theorem:

a^{2} +b^{2} =c^{2}

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 4

b = 6

c = unknown

^^^Plug these numbers into the theorem

4^{2} +6^{2} =c^{2}

simplify

16 + 36 = x^{2}

52 = x^{2}

To remove the square from x take the square root of both sides to get you...

√52 = x  

^^^Unsimplified radical

2√13

^^^Simplified radical

7.21

^^^Rounded to hundedths

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0
4 years ago
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
Simplify the expression 2j+4j+j+7
Alina [70]

Answer:

7j+7

Step-by-step explanation:

2j+4j+j+7

combine like terms

7j+7

Sorry I don't really know how to explain it, but you just have to combine terms with the same unit

3 0
3 years ago
Which number is less than 8/3​
Zarrin [17]

Answer:

A I belive

Step-by-step explanation:

Just divide the top number with the bottom

4 0
3 years ago
I will give brainliest to correct answer
FromTheMoon [43]

Answer:

D

Step-by-step explanation:

If the polynomial p(x) is divided by a polynomial of the form x+k (which accounts for all of the possible answer choices in this question), the result can be written as

p(x)/x+k = q(x) + r/x+k

where q(x) is a polynomial and r is the remainder. Since x+k is a degree-1 polynomial (meaning it only includes x^{1} and no higher exponents), the remainder is a real number.

Therefore, p(x) can be rewritten as p(x) = (x+k)q(x) + r, where r is a real number.

The question states that p(3) = −2, so it must be true that

−2 = p(3) = (3+k)q(3) + r

Now we can plug in all the possible answers. If the answer is A, B, or C, r will be 0, while if the answer is D, r will be −2.

A. −2=p(3)=(3+(−5))q(3)+0

−2=(3−5)q(3)

−2=(−2)q(3)

This could be true, but only if q(3)=1

B. −2=p(3)=(3+(−2))q(3)+0

−2=(3−2)q(3)

−2=(−1)q(3)

This could be true, but only if q(3)=2

C. −2=p(3)=(3+2)q(3)+0

−2=(5)q(3)

This could be true, but only if q(3) = −2/5

D. −2=p(3)=(3+(−3))q(3)+(−2)

−2=(3−3)q(3)+(−2)

−2=(0)q(3)+(−2)

This will always be true no matter what q(3) is.

Of the answer choices, the only one that must be true about p(x) is D, that the remainder when p(x) is divided by x−3 is -2.

The final answer is D.

6 0
3 years ago
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