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Digiron [165]
3 years ago
6

The function F(x)=log0.75^x is decreasing. True or false

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0
We're given the following function:
f(x)=log(.75^x)=log[  (\frac{3}{4}) ^{x}]=log( \frac{3^x}{4^x})

In order to see if the function is decreasing we'll take its derivative. If \frac{d}{dx}f(x)\ \textgreater \ 1 the function is increasing, if \frac{d}{dx}f(x)\ \ \textless \  \ 1 the function is decreasing.

We take the derivate:
\frac{d}{dx}[log( \frac{3^x}{4^x})]= \frac{4^x}{3^x}[ \frac{d}{dx} (\frac{3^x}{4^x})]=\frac{4^x}{3^x} \frac{4^x[ \frac{d}{dx} (3^x)]-3^x[ \frac{d}{dx} (4^x)]}{ 4^2^x}=
\frac{4^x}{3^x} \frac{4^x[3^xlog(3)]-3^x[4^x[4^xlog(4)]}{ 4^2^x}=log(3)-log(4)\ \textless \ 0

Which implies the function is decreasing.

Another way to answer the problem (although less insightful) you can take any two real numbers k and q such that k\ \textgreater \ q, then if f(k)-f(q)\ \textgreater \ 0 the function is increasing and if f(k)-f(q)\ \textless \ 0 the function is decreasing. You can verify the function is decreasing with any two numbers in the function's domain.
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