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3 years ago

0.01L = how many ML????????

Mathematics

2 answers:

jasenka [17]3 years ago

5 0

Your answer would be ten

Sliva [168]3 years ago

3 0

0.01L = 10 ML
hope it helps

because 1L = 1,000ML

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A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.

Vlada [557]

Answer:

a) $y=12000(2)^{\frac{t}{50}}$

b) Approx. 27,569 bacteria

c) About 103 minutes

Step-by-step explanation:

This will follow exponential modelling with form of equation shown below:

$y=Ab^{\frac{t}{n}}$

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

$y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}$

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

$y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76$

The number of bacteria after 1 hour would approximate be <u>27,569 bacteria</u>

<u></u>

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

$y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103$

After about 103 minutes, there will be 50,000 bacteria

4 0

3 years ago

The sum of three numbers is 26. Twice the first minus the second is the third less 2. The third is the second minus 3 times the

Agata [3.3K]

Let a, b, c represent the three numbers. The problem statement gives rise to three equations:

a +b +c = 26
2a -b = c -2
-3a +b = c

Adding the first two equations gives

... (a +b +c) +(2a -b) = (26) +(c -2)

... 3a +c = 24 +c . . . . . simplify

... 3a = 24 . . . . . . . . . . subtract c

... a = 8 . . . . . . . . . . . . divide by 3

Adding the second and third equations gives ...

... (2a -b) +(-3a +b) = (c -2) +(c)

... -a = 2c -2 . . . . simplify

... -6 = 2c . . . . . . add 2, substitute for a

... -3 = c . . . . . . . . divide by 2

Using the third equation we can find b.

... -3·8 +b = -3 . . . . substitute for a and c

... b = 21 . . . . . . . . .add 24

The numbers are 8, 21, -3.

_____

The method above is sort of "ad hoc", taking advantage of the numbers in this particular set of equations. You can use more formal methods of Gaussian elimination or Cramer's Rule to solve these by just following a procedure. Or, your graphing calculator can do it for you.

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3 years ago

Use the quadratic formula to solve x2+7x+3. Show all of your work. Then describe the solution.

Mariana [72]

Answer:

Step-by-step explanation:

The coefficients of the quadratic x^2 + 7x + 3 are a = 1, b = 7 and c = 3.

The discriminant is b^2 - 4ac, or 49 - 4(1)(3), or 49-12, or 37.

Because the discriminant is positive, we know that this quadratic equation has two real, different solutions.

-7 ± √37

x = --------------- => x = (-7 + √37)/2 and x = (-7 - √37)/2

In words: This quadratic equation has two real, unequal solutions involving the radicand 37.

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3 years ago

30% of what equals 60

Elena-2011 [213]

Create an inequality
x/60 = 30/100
x = 200
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3 years ago

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Answer:

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3 years ago