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3 years ago

What is the solution to {4x - y = 8 {6x + y = 2

1 answer:

7 0

$4x - y = 8 \\ + 6x + y = 2 \\ = = = = = = = = \\ 10x = 10 \\ 10 \div 10 = 1 \\ x = 1 \\ \\ \\ 6x + y = 2 \\ 6(1) + y = 2 \\ 6 + y = 2 \\y = 2 - 6 \\ y = - 4 \\ \\ \\ \\ check \\ \\ 6x + y = 2 \\ 6(1) + y( - 4) = 2 \\ 6 - 4 = 2 \\ 2 = 2$

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pantera1 [17]

Answer:

third option

Step-by-step explanation:

Given f(x) has zeros x = a, x = b, then

the factors are (x - a), (x - b) and the polynomial is the product of the factors.

Complex zeros occur as conjugate pairs, thus

5 + 4i is a zero then 5 - 4i is a zero

The zeros are x = 3, x = - 13, x = 5 + 4i, x = 5 - 4i, thus the factors are

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(x - 3), (x + 13), (x - 5 - 4i), (x - 5 + 4i)

= (x - 3), (x + 13), ((x - 5) - 4i), ((x - 5) + 4i)

The polynomial is the product of the factors

f(x) = (x - 3)(x + 13)((x - 5) - 4i)((x - 5) + 4i) ← expand factors in pairs

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= (x² + 10x - 39)(x² - 10x + 25 + 16)

= (x² + 10x - 39)(x² - 10x + 41) ← distribute

= $x^{4}$ - 10x³ + 41x² + 10x³ - 100x² + 410x - 39x² + 390x - 1599 ← collect terms

= $x^{4}$ - 98x² + 800x - 1599

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