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Semenov [28]
3 years ago
15

Solve by using the measurements ∠PQR = 90°, ∠QRP = 80°, and r = 15. Round measures of sides to the nearest tenth and measures of

angles to the nearest degree.

Mathematics
2 answers:
Flura [38]3 years ago
7 0

Answer:

q ≈ 15.2

p ≈ 2.5

Step-by-step explanation:

Given that:

  • ∠PQR = 90°
  • ∠QRP = 80°
  • r = 15

We need to find the length of side q and  p

Use the sine law to find out q, we have:

sin(QRP) = \frac{r}{q}

<=> sin(80°) = \frac{r}{q}

<=> q = \frac{r}{sin(80)} = \frac{15}{0.98}   ≈ 15.2

Because PQR is a right triangle, so we use pytagon theorem to find p

q^{2} = r^{2} + p^{2}

<=> p^{2} = q^{2} - r^{2}

<=> p^{2} = 15.2^{2} - 15^{2} = 6.04 \\

<=> p = \sqrt{6.04} ≈ 2.5

valkas [14]3 years ago
5 0

Good evening ,

___________________

Step-by-step explanation:

Look at the photo below for the answer.

:)

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