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3 years ago

15

Solve by using the measurements ∠PQR = 90°, ∠QRP = 80°, and r = 15. Round measures of sides to the nearest tenth and measures of

angles to the nearest degree.

2 answers:

Flura [38]3 years ago

7 0

Answer:

q ≈ 15.2

p ≈ 2.5

Step-by-step explanation:

Given that:

∠PQR = 90°
∠QRP = 80°
r = 15

We need to find the length of side q and p

Use the sine law to find out q, we have:

sin(QRP) = $\frac{r}{q}$

<=> sin(80°) = $\frac{r}{q}$

<=> q = $\frac{r}{sin(80)}$ = $\frac{15}{0.98}$ ≈ 15.2

Because PQR is a right triangle, so we use pytagon theorem to find p

$q^{2} = r^{2} + p^{2}$

<=> $p^{2} = q^{2} - r^{2}$

<=> $p^{2} = 15.2^{2} - 15^{2} = 6.04 \\$

<=> p = $\sqrt{6.04}$ ≈ 2.5

valkas [14]3 years ago

5 0

Good evening ,

___________________

Step-by-step explanation:

Look at the photo below for the answer.

:)

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