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2 years ago

A 90 kg body is taken to a planet where the acceleration due to

Physics

1 answer:

yawa3891 [41]2 years ago

6 0

Answer:

225 kg.

Explanation:

Since the gravity is 2.5 times than that of the Earth, g on that planet = (10 * 2.5) m/s = 25 m/s.

Hence, the weight of the body would be (90 * 2.5) kg, aka 225 kg.

Hope this helped!

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A4 kg bowling ball begins rolling down a at bowling alloy at 6 m/s . When it strikes the pins, it is estimated to be moving at 5

Paul [167]

Answer:

Energy lost due to friction is 22 J

Explanation:

Mass of the ball m = 4 kg

Initially velocity of ball v = 6 m/sec

So kinetic energy of the ball $KE=\frac{1}{2}mv^2$

$KE=\frac{1}{2}\times 4\times 6^2=72J$

Now due to friction velocity decreases to 5 m/sec

Kinetic energy become

$KE=\frac{1}{2}\times 4\times 5^2=50J$

Therefore energy lost due to friction = 72 -50 = 22 J

8 0

2 years ago

Particle 1 and particle 2 have masses of m1 = 2.2 × 10-8 kg and m2 = 4.8 × 10-8 kg, but they carry the same charge q. The two pa

Lorico [155]

Answer: $r_2=11.81 cm$

Explanation:

Given

$m_1=2.2\times 10^{-8} kg$

$m_2=4.8\times 10^{-8} kg$

same charge on both masses

potential Energy due to Magnetic Field =Kinetic Energy of Particle

$qV=\frac{mv^2}{2}$

$v=\sqrt{\frac{2qV}{m}}$

and we know

Force due to magnetic field will Provide centripetal Force

$qvB=\frac{mv^2}{r}$

$B=\frac{\sqrt{\frac{2Vm}{q}}}{r}$

and B is equal for both particles

thus $\frac{m}{r^2}=constant$

$\frac{m_1}{r_1^2}=\frac{m_2}{r_2^2}$

$r_2^2=\frac{4.8}{2.2}\times 8^2$

$r_2=11.81 cm$

4 0

2 years ago

Explain why the extrapolated temperature is used to determine the maximun temperature of the mixture rather than the highest rec

Oksi-84 [34.3K]

The extrapolated temperature is used to define the maximum temperature of the mixture relatively than the highest recorded temperature in which the conclusion will effect in a higher specific heat value. Heat is bound to escape from whatever apparatus is using, therefore it is needed to account for the loss of the heat that does not go into increasing the temperature of the mixture.

6 0

3 years ago

Read 2 more answers

Vertical Motion

harina [27]

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3 0

2 years ago

This should be correct

sweet-ann [11.9K]

Maybe it is, maybe it isn't. We can't tell, until we see what "this" is.

Show us a drawing, an equation, an expression, a statement ... something !

5 0

3 years ago