A car on a straight road starts from rest and accelerates at 2.0 meter per second over a distance of 50 meters. Calculate the ma
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Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.
Now here we will do the components of the weight of the person
given that weight of the person = 500 N
now its components are
now here as we can say that one of the component is balanced here by the normal force perpendicular to plane
while the other component of the weight is balanced by the force applied on the rope
So here the force applied on the rope will be given as
so it apply 300 N force along the inclined plane