A car on a straight road starts from rest and accelerates at 2.0 meter per second over a distance of 50 meters. Calculate the ma
1 answer:
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Answer:
a) v = 1.075*10^7 m/s
b) FB = 7.57*10^-12 N
c) r = 10.1 cm
Explanation:
(a) To find the speed of the alpha particle you use the following formula for the kinetic energy:
(1)
q: charge of the particle = 2e = 2(1.6*10^-19 C) = 3.2*10^-19 C
V: potential difference = 1.2*10^6 V
You replace the values of the parameters in the equation (1):
The kinetic energy of the particle is also:
(2)
m: mass of the particle = 6.64*10^⁻27 kg
You solve the last equation for v:
the sped of the alpha particle is 1.075*10^6 m/s
b) The magnetic force on the particle is given by:
B: magnitude of the magnetic field = 2.2 T
The direction of the motion of the particle is perpendicular to the direction of the magnetic field. Then sinθ = 1
the force exerted by the magnetic field on the particle is 7.57*10^-12 N
c) The particle describes a circumference with a radius given by:
the radius of the trajectory of the electron is 10.1 cm
Two forces 3N and 4N act on a body in a direction due north From East, the equilibrant's angle is given by .
The equilibrium force is the balanced force when the net force acting is zero and is the exact opposite of the consequent force. The resultant force is one single force replaced by numerous forces.
<h3>Briefing:</h3>3N and 4N are the two forces pulling on a body.
The forces work along the North and the East, which are perpendicular to one another.
The resultant of the forces, which is provided by the equilibrant force,
R = √(3)²+(4)²
R = 5N
From East, the equilibrant's angle is given by
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