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Reil [10]
3 years ago
15

Talia took the bus from her home to the bank and then walked back to her home along the same route. The round trip took 0.9 hour

s total. The bus traveled at an average speed of 40 km/h and she walked at an average speed of 5 km/h. Use the table to complete these statements. What is the rate of trip two?
Mathematics
1 answer:
qaws [65]3 years ago
5 0
Just set up the equation and solve for x, that is the time.

40(0.9-x) = 5x
36 = 45x
x = 36/45
 x = 0.8

It took Talia 0.8 hours (48 minutes) to walk home. 
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4 years ago
PLZZZ HELP WILL GIVE BRAINN
Hatshy [7]

Answer:

Whole numbers: 56

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Integer: -5

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Natural numbers: 0

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3 years ago
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Suppose that the waiting time for a license plate renewal at a local office of a state motorvehicle department has been found to
zysi [14]

The probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.

Given mean of 30 minutes and standard deviation of 7.5 minutes.

In a set with mean d and standard deviation d. , the z score is given as:

Z=(X-d)/s.

where d is sample mean and s is standard deviation.

We have to calculate z score and then p value from normal distribution table.

We have been given d=30, s=7.5

p value of Z when X=44 subtracted by the p value of Z when X=16.

When X=44,

Z=(44-30)/7.5

=14/7.5

=1.87

P value=0.9686

When X=16

Z=(16-30)/7.5

=-1.87

P Value=0.0314.

Required probability is =0.9686-0.0314

=0.9372

=93.72%

Hence the probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.

Learn more about z test at brainly.com/question/14453510

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7 0
2 years ago
Leona has a bag containing letter tiles. Which describes dependent events?
serious [3.7K]

Answer:

a) removing a vowel, not replacing it, and then removing another vowel

Step-by-step explanation:

This question is from the topic Probability. In Probability, a dependent event is one in which the outcome of one event alters or changes the outcome of another event. <u>A classic example of this is seen when sampling without replacement is done</u>. When sampling without replacement is done, the outcome of another event within the same set changes. When sampling with replacement is done, the outcome of the events are independent because every item in the population still has an equal chance of being chosen. However, in the case of sampling without replacement, once an item has been selected from a population, the outcome of every other event after it is altered based on the item that was initially chosen.

Let's assume that the bag has 26 tiles (one for each alphabet from a - z)

Population = 26, consonant = 21, vowel = 5

If a vowel or consonant is removed & is replaced, we have:

Pr (choosing "a") = number of item ÷ population

Pr = 1 ÷ 26 = 1/26

Pr (choosing "y") = 1 ÷ 26 = 1/26

Doing this for over & over again, produces the same probability

However, if an item was selected without replacement, we have:

Pr (choosing "a") = 1 ÷ 26 = 1/26

Without replacement implies that if I choose tile letter "a", tile letter "a" will not be included in subsequent events, hence:

Population = 25

Pr (choosing "u") = 1 ÷ 25 = 1/25

Without replacement, population = 24

Pr (choosing "y") = 1 ÷ 24 = 1/24

So, we see the dependent nature of the events in how that the outcome of the next event is being altered. <u>As such, </u><u>option a</u><u> describes a dependent event & is the correct answer</u>

8 0
3 years ago
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