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Artyom0805 [142]
3 years ago
11

Ruben has two congruent wooden dowels. He cuts one dowel in two in order to have three pieces to make a triangle. Explain why, d

espite having three sides, Ruben will not be able to make a triangle with his three pieces?
Mathematics
2 answers:
e-lub [12.9K]3 years ago
4 0
Let us use the Pythagorean theorem in identifying what triangle can be formed.

Let us assume that the 2 wooden dowels each measure 8 inches. We cut off one wooden dowel into half, so it becomes 2 pcs of 4 inches each.

The 3 wooden dowels now measure, 4 inches, 4 inches, and 8 inches. 

The Pythagorean theorem states: 

a² + b² = c²
4² + 4² = 8²
16 + 16 = 64
34 ≠ 64

The measure of the cut wooden dowel must be longer than the uncut wooden dowel to create a triangle. 

I also tried this on a piece of paper, I cut each piece according to the assumed measure. No triangle can be formed under this activity. 
Slav-nsk [51]3 years ago
3 0

It is given in the question that

Ruben has two congruent wooden dowels. He cuts one dowel in two in order to have three pieces to make a triangle.

First we have to check out triangle inequality theorem, which is sum of two sides of a triangle must be greater then the third side .

But here the sum of two pieces of the cutted dowel is equal to the lenth of the first dowel.

SO here triangle inequality theorem is not following .

Hence , Ruben will not be able to make a triangle with his three pieces.

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Answer:

a. \frac{dT}{dt}=k(T-Tm); T(0)=190

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d. t=153.39838\\ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

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\frac{dT}{dt}=k(T-Tm); T(0)=190

b. The differential equation obtained is a differential equation of separable variables:

\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122

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T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259

d.

150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\

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