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3 years ago

OMG PLEASE HELP IF YOU CAN 14 POINTS!!!!!! For each function what is the output for the given input? f(x) = 5x+1, find f(-4)

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

3 0

<span>f(x) = 5x+1
f(-4) = 5(-4) + 1 = -20 + 1 = -19

hope that helps
</span>

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3 years ago

Which trigonometric function has a range that does not include 0.4?

Montano1993 [528]

<h2>Hello!</h2>

The answer is: $y=cscx$

Domain and range of trigonometric functions are already calculated, so let's discard one by one in order to find the correct answer.

The range is where the function can exist in the vertical axis when we assign values to the variable.

First:

$y=cosx$ : Incorrect, it does include 0.4 since the cosine range goes from -1 to 1 (-1 ≤ y ≤ 1)

Second:

$y=cotx$ : Incorrect, it also does include 0.4 since the cotangent range goes from is all the real numbers.

Third:

$y=cscx$ : Correct, the cosecant function is all the real numbers without the numbers included between -1 and 1 (y≤-1 or y≥1).

Fourth:

$y=sinx$ : Incorrect, the sine function range is equal to the cosine function range (-1 ≤ y ≤ 1).

I attached a pic of the csc function graphic where you can verify the answer!

Have a nice day!

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3 years ago

What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9

skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let $u^2=x^4\\u = x^2$

Subbing in:

$9u^2-2u-7=0$

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:

$9u^2-9u+7u-7=0$

Group together in groups of 2:

$(9u^2-9u)+(7u-7)=0$

Now factor out what's common within each set of parenthesis:

$9u(u-1)+7(u-1)=0$

We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:

$(u-1)(9u+7)=0$

Remember that $u=x^2$

so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.

$(x^2-1)(9x^2+7)=0$

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring $(x^2-1)$ gives us that x = 1 and -1. The other set is a bit more tricky. If