The horizontal distance between light house and boat is 1588.78 feet approximately.
The figure is given by,
Here, AB = height of the lighthouse bacon light above the water = 139 feet
Now angle ACB = 5 degree
Let the horizontal distance of light house from the boat = BC = x feet
So by trigonometric function we get,
tan 5 = AB/BC
tan 5 = 139/x
x = 139/tan 5 = 1588.78 (approximately)
Hence the horizontal distance between light house and boat is 1588.78 feet approximately.
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Answer:
13
Step-by-step explanation:
Use photomath. Do not click on the link the other person which is actually a bot put.
The system of equations are p = 150 + 5n and p = 15n
<u>Solution:</u>
Given that, The Parks and recreation department in your town offers a season pass for $150.
With the season pass you pay $5 per session to use the town's tennis courts.
Without the season pass you pay $15 per session to use the tennis courts.
We have to write a system of equations to represent the situation
Now, let the number of sessions be "n" and total paying amount be "p"
<em><u>Then in case of taking season pass </u></em>
total amount = season pass cost + $5 per session
p = 150 + 5 x n
p = 150 + 5n
<em><u>And in case of no season pass</u></em>
total amount = 15 per session
p = 15 x n
p = 15n
Hence, the system of equations are p = 150 + 5n and p = 15n
