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Julli [10]
4 years ago
11

Which expression is equivalent to 7 sqrt x^2/5 sqrt y^3

Mathematics
2 answers:
spin [16.1K]4 years ago
7 0

Answer:

Option A x^{\frac{2}{7}}*y^{-\frac{3}{5}}

Step-by-step explanation:

we have

\frac{\sqrt[7]{x^{2}}}{\sqrt[5]{y^{3}}}

we know that

\sqrt[7]{x^{2}}=x^{\frac{2}{7}}

\sqrt[5]{y^{3}}=y^{\frac{3}{5}}

substitute in the expression

\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}=x^{\frac{2}{7}}*y^{-\frac{3}{5}}

nasty-shy [4]4 years ago
4 0

Answer:

The correct option is 1

Step-by-step explanation:

Given the expression

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}

we have to simplify the above

\sqrt[7]{x^2}=(x^2)^{\frac{1}{7}}=x^{\frac{2}{7}}

\sqrt[5]{y^3}=(y^3)^{\frac{1}{5}}=y^{\frac{3}{5}}

The expression becomes

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}=[x^{\frac{2}{7}}][y^{\frac{-3}{5}}]

Hence, the correct option is 1

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