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miv72 [106K]
3 years ago
7

Diego was asked to plot these points: (-50, 0), (150, 100), (200, -100), (350, 50), (-250, 0). What interval could he use for ea

ch axis? Explain your reasoning.
Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

Interval of 50 on both axis

Step-by-step explanation:

Given

(x_1,y_1) = (-50,0)

(x_2,y_2) = (150,100)

(x_3,y_3) = (200,-100)

(x_4,y_4) = (350,50)

(x_5,y_5) = (-250,0)

There are several ways to do this, but I will use the observation method, since the dataset is small.

Considering the x-coordinates

x = \{-50,150,200,350,-250}

Each element of the data set is a multiple of 50.

Hence, an interval of 50 can be used on the x-axis

Considering the y-coordinates

y = \{0,100,-100,50,0\}

Each element of the data set is a multiple of 50.

Hence, an interval of 50 can be used on the y-axis

<em>So, an interval of 50 can be used on both axes</em>

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Answer:

Step-by-step explanation:

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b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

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February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

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