Answer:
d.
Step-by-step explanation:
Left line is defined when x < 1 (x is less than 1). The point is not full and that means that x = 1 is not included.
Right line is defined when x is greater or equal to one x ≥ 1.
Options that have x < 1 and x ≥ 1 are b and d, so the answer is one of those.
Equations of the lines are in slope-intercept form y = mx + b, where m is slope and b is y-intercept.
Right line has steeper slope than left line, so the slope of right line will have bigger absolute value. That is the case with option d. (Left line has slope -1 and right one has slope -2, absolute value of right slope is bigger.)
You could also check with y-intercepts. Left line has y-intercept at y = 2 and left line is defined when x < 1. Only option d meets these conditions.
I believe the answer would be C; but I'm not sure if this is the right category for this question?
Answer:
Well first you put the y-intercept on the graph. In this case it would be 15
So graph the point (0,15)
The you do the slope which is 3
so you always do rise over run for slope.
If 3 were a fraction it would be 3/1 so go up 3 points and the go right 1 point from (0,15)
hope this helps .-.
