All categories

2 years ago

What is the mean of this data set 82,105,247,119,94,202

Mathematics

2 answers:

Kazeer [188]2 years ago

6 0

To find the mean, add the numbers, and divide by the amount of numbers there is.

(82 + 105 + 247 + 119 + 94 + 202)/6

Simplify. Remember to follow PEMDAS. First, add

(849)/6

Next, divide by 6

849/6 = 141.5

141.5 should be your answer

hope this helps

pickupchik [31]2 years ago

6 0

Hello There!

The mean is the average of numbers in a set of data or numbers.

Step 1: Add the numbers in the data set. In this case, we would add

82 + 105 + 247 + 119 +94 +202 = 849

Step 2: Divide the sum by the number of digits you added. In this case, you

would divide 849 by 6 and you would get a quotient of 141.5

The Mean For This Set Of Data Would Be 141.5

You might be interested in

6: REDUCE to simplest term. 4/1 + 15/2

vovangra [49]

Answer:

$\frac{4}{15}+\:\frac{1}{2}$ in the simplest term is:

$\frac{4}{15}+\frac{1}{2}=\frac{23}{30}$

Step-by-step explanation:

Given the expression

$\frac{4}{15}+\:\frac{1}{2}$

Thus, solving to reduce to the simplest term

$\frac{4}{15}+\frac{1}{2}$

LCM of 15, 2: 30

Adjusting fraction based on the LCM

so the expression becomes

$\frac{4}{15}+\:\frac{1}{2}=\frac{8}{30}+\frac{15}{30}$

Apply the fraction rule: $\frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}$

$=\frac{8+15}{30}$

Add the numbers: 8+15 = 23

$=\frac{23}{30}$

Therefore, $\frac{4}{15}+\:\frac{1}{2}$ in the simplest term is:

$\frac{4}{15}+\frac{1}{2}=\frac{23}{30}$

4 0

2 years ago

If 4x^2 - 100 = 0, what are the roots of the equation?

drek231 [11]

The roots to this equation i s either positive or negative five

8 0

2 years ago

Read 2 more answers

What is the rule for this pattern? 1st term:32, 2nd term:36, 3rd term:40

Alenkasestr [34]

Answer:

Add four to each sum

Step-by-step explanation:

32, 36, 40

32 + 4 = 36

36 + 4 = 40

Rule: Add four to each sum

Hope this helped!

(Let me know if I got something wrong!)

4 0

2 years ago

Read 2 more answers

PLEASE HELP ASAP 25 POINTS

Lisa [10]

We're going to go ahead and eliminate one answer out of the four. It cannot be B (the second answer) because the graph is made of dotted lines.

Dotted Lines = > or <

Solid Lines = ≤ or ≥

Next, let's focus on the straight line on the graph.

The equation for the line is

y = x - 4

Since the shaded region is below the line,

the equation will be y < x - 4

We can now eliminate answer A

Since the second equation is y < - l x - 2 l

It will be shaded below the graph since it uses the ( < ) (less than symbol)

This means the answer is C

Hope I helped, message me if you have any questions : )

8 0

3 years ago

A bus travels on an east-west highway connecting two cities A and B that are 100 miles apart. There are 2 services stations alon

melamori03 [73]

Answer:

51/4

Step-by-step explanation:

To begin with you have to understand what is the distribution of the random variable. If X represents the point where the bus breaks down. That is correct.

X~ Uniform(0,100)

Then the probability mass function is given as follows.

$f(x) = P(X=x) = 1/100 \,\,\,\, \text{if} \,\,\,\, 0 \leq x \leq 100\\f(x) = P(X=x) = 0 \,\,\,\, \text{otherwise}$

Now, imagine that the D represents the distance from the break down point to the nearest station. Think about this, the first service station is 20 meters away from city A, and the second station is located 70 meters away from city A then the mid point between 20 and 70 is (70+20)/2 = 45 then we can represent D as follows

$D(x) =\left\{ \begin{array}{ll} x & \mbox{if } 0\leq x \leq 20 \\ x-20 & \mbox{if } 20\leq x < 45\\ 70-x & \mbox{if } 45 \leq x \leq 70\\ x-70 & \mbox{if } 70 \leq x \leq 100\\ \end{array}\right.$

Now, as we said before X represents the random variable where the bus breaks down, then we form a new random variable $Y = D(X)$ , $Y$ is a random variable as well, remember that there is a theorem that says that

$E[Y] = E[D(X)] = \int\limits_{-\infty}^{\infty} D(x) f(x) \,\, dx$

Where $f(x)$ is the probability mass function of X. Using the information of our problem

$E[Y] = \int\limits_{-\infty}^{\infty} D(x)f(x) dx \\= \frac{1}{100} \bigg[ \int\limits_{0}^{20} x dx +\int\limits_{20}^{45} (x-20) dx +\int\limits_{45}^{70} (70-x) dx +\int\limits_{70}^{100} (x-70) dx \bigg]\\= \frac{51}{4} = 12.75$

3 0

3 years ago