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Lady bird [3.3K]
3 years ago
9

Harriet is comparing the costs of calling cards. To use card A, the cost is $1.00 to connect and then $0.04 per minute. To use c

ard B, it costs $0.65 to connect and then $0.06 per minute. For what number of minutes does it cost the same amount to use each card for a single call?
Mathematics
2 answers:
svetlana [45]3 years ago
7 0
1 + .04m = .65 + .06m 1 - .65 = .06m - .04m .35 = .02x .35/.02 = x 17.5 = x
MrMuchimi3 years ago
3 0

Answer: There are 17.5 minutes for which it costs the same amount to use each card for a single call.

Step-by-step explanation:

Let the number of minutes be x

To use card A, the cost is $1.00 to connect and then $0.04 per minute.

So, our expression becomes,

1+0.04x

To use card B, the cost is $0.65 to connect and then $0.06 per minute.

So, our expression becomes,

0.65+0.06x

According to question, if it cost the same amount to use each card for a single call, then it will be

1+0.04x=0.65+0.06x\\\\1-0.65=0.06x-0.04x\\\\0.35=0.02x\\\\\frac{0.35}{0.02}=x\\\\17.5=x

Hence, there are 17.5 minutes for which it costs the same amount to use each card for a single call.

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On analyzing the question we can say that the angle ∠JKM of the triangle ΔJKL would be 42 as line MK bisects ∠JKL into ∠JKM & ∠MKL.

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Therefore, as we have given  m∠JKL = 84 & m∠MKL  = 42

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1 year ago
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