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3 years ago

What is the measure of each intercepted arc for each inscribed angle of a square inscribed in a circle?

Mathematics

1 answer:

julsineya [31]3 years ago

6 0

Answer:

The measure of the angle of each of the intercepted arc is 180°

Step-by-step explanation:

An intercepted arc is an encased (between chords) portion of the circumference of the circle. The chords that form the intercepted arc meet at a point

An inscribed angle is the angle is an angle formed between two chords that meet at a point called the end point

For the inscribed square, the symmetry has it that the diagonal is the same as the diameter of the circle as the diagonals bisect each other having equal distances on either side to the circumference of the circle.

Given that the angles in the vertices of the square are 90° and the point of intersection of the two chords forming the vertex are at the ends of the diameter of the circle, which passes through the center of the circle, the angle 90° at the vertex is half the angle at the center which is the angle of the intercepted arc

∴ The measure of the angle of each of the intercepted arc = 2× 90 = 180°.

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Equation with angles can someone please answer helpppp

Elden [556K]

Answer:

$x = 18°\\\angle A = 73°$

Step-by-step explanation:

By interior angle property on one side of the transversal.

$\angle A+ \angle B = 180°\\6x - 35° + 3x + 53° = 180°\\9x + 18° = 180°\\9x = 180° - 18°\\9x = 162°\\x = \frac{162°}{9}\\ \huge \red {\boxed {x = 18°}} \\\therefore \angle A = 6x - 35°\\\therefore \angle A = 6\times 18°- 35°\\\therefore \angle A = 108°- 35°\\ \huge \purple {\boxed{\therefore \angle A = 73°}} \\$

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3 years ago

576 is what percent of 800?

aleksley [76]

72 percent.
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3 years ago

Read 2 more answers

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

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3 years ago

What are the approximate values of the minimum and maximum points of

Katen [24]

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3 years ago

A soccer team won 30% of their games and won 40 games. how many games did they play?

sweet [91]

Answer:

Step-by-step explanation:

i added 30% and 40

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3 years ago