Answer:
1. 5x +43
2. -1.5x - 7
3. 6.2 - 2x
Step-by-step explanation:
<u />
<u>Equation 1:</u>
5 (x+8) +3
First, we can distribute the 5 to the (x+8) and get 5x + 40. Distributing is when we multiply the 5 by the first number (x) and then by the second number (8) Because they aren't like terms (don't both have x's) we cannot combine then and must keep them separated by a subtraction sign
Now we have: 5x + 40 + 3
Next, we can combine the like terms. This means that any that have the same variable can be combined. So, the 5x has no other x's so he has to stay how he is. The 40 and the 3, however, can be added together to get 43.
Our finished equation is: 5x + 43
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<u>Equation 2:</u>
3.6x - 7 - 5.1x
First, we can combine like terms as we learned in the last problem. This would be our x's since we have multiple.
We can add 3.6x and -5.1x and get -1.5x
Now we have: -1.5x - 7
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<u>Equation 3:</u>
4 + 8x + 2.2 - 10x
We can start with either the numbers with x's or without but I'll just do the x's. So we have 8x and -10x. Adding these together would get us -2x.
Next, we can combine 4 and 2.2 and get 6.2.
Now, putting these back into our equation would look like this:
6.2 - 2x
I'm not sure how much my explanations helped, but I hope you understand!!
when the degree of the denominator is greater than that of the numerator, the only horizontal asymptote occurs at y = 0.
3. The original sequence
TAC - CGC - TTA - CGT - CTG - ATC - GCT
codes for
tyr - arg - leu - arg - leu - ile - ala
while the mutated sequence codes for
TAC - CGC - TTA - TTA - TTA - CGT - G<u>CT</u> - <u>G</u>CT - ATC - GCT
tyr - arg - leu - leu - leu - arg - <u>ala</u> - ala - ile - ala
There are several frameshift mutations involved here:
• the first inserts 6 bases (TTA - TTA)
• the second inserts 1 base (G) before the CTG triplet (underlined)
• the third inserts 2 bases (CT) after the CTG triplet
4. The original sequence is the same as before. The mutated sequence
TAC - CGC - TAA - TTA - TTA - CGT - G<u>CT</u> - <u>G</u>CT - ATC - GCT
codes for
tyr - arg - STOP - leu - leu - arg - ala - ala - ile - ala
Then
• there is a (nonsense) point mutation that swaps T for A in the original TTA triplet (nonsense since it produces a stop codon that would halt replication/expression)
• there is a frameshift mutation that inserts 3 bases (TTA)
as well as two other frameshift mutations that also occurred in the previous part.
Answer:
10 full hours (10.224 is exact)
Step-by-step explanation: