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Romashka [77]
2 years ago
6

Solve the system of linear equations by elimination.

Mathematics
1 answer:
aleksley [76]2 years ago
3 0

Answer:

This is my best solution for your question

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For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
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3 years ago
5/6 of 15 i need help????????????
emmainna [20.7K]

Answer: 12.5 or 12 1/2

Step-by-step explanation:

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Answer:

Multiply by 5

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balu736 [363]

Answer:

Step-by-step explanation:

Use vertical angles to help solve the problem. Angles that are across from each other are congruent. For exmaple,  <2 = 85 degrees because the angle across from it is 85 degrees. I assume angle 1 is 95 degrees, so angle 3 would also be 95 degrees.

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I hope this helps :)

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