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3 years ago

Describe three safety procedures you should always follow when conducting a scientific investigation.

Physics

2 answers:

Sunny_sXe [5.5K]3 years ago

7 0

Answer:

(1) Follow the instruction.

(2) Know the location of safety instrument.

(3) Lab dress.

Explanation:

There are the three procedures we can take follow when conducting a scientific investigation:

(1) Follow the instruction: It is the most important procedure while performing any scientific investigation. Whether you listen to the lab attendent instruction, or your supervisor instruction, or the instruction which are given in the book. It is very important.

(2) Know the location of safety instrument: If any instrument is not working properly, it is very important to know the safety location of that instrument and it is quite important to know that some instrument is working or not.

(3) Lab dress: It is very important thing while doing an investigation. We should wear lab coats and gloves because gloves will protect you from any contact with the chemical, which will give serious injuries like hand burns.

SOVA2 [1]3 years ago

5 0

1) check your tools for chips or breaks before beginning your experiment.
2) keep your work surface neat and clean
3) read and follow safety instructions and the materials you will need to use in the investigation.

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Mr. Adams asked his students to write the chemical symbol for the element zinc. He wrote the students’ answers on the whiteboar

m_a_m_a [10]

The chemical symbol for the element zinc is Zn.

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A chemical element is the one which reacts with other elements to form a compound.

Any chemical symbol must have its first letter written in Uppercase. If the element has two letter chemical symbol, then it should be written in lowercase.

Thus, the student wrote Zn as the chemical symbol of Zinc on the whiteboard.

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2 years ago

Por una espira de 0.5 m2 de área circula una corriente de 5 A. Calcula la densi- dad de flujo magnético B considerando que la es

Sloan [31]

Answer:

$\beta=B=8.05\mu T$

Explanation:

The density of the magnetic flux is given by the following formula:

$\beta=\frac{\Phi_B}{A}=\frac{ABcos\theta}{A}=Bcos\theta$

The normal vector A and the vector of the magnitude of the magnetic field are perpendicular, then, the angle is zero:

The magnitude of the magnetic field is calculated by using the formula for B at a distance of x to a point in the plane of the loop:

$B=\frac{\mu_oIR^2}{2(x^2+R^2)^{3/2}}$

For x = 0 you have:

$B=\frac{\mu_oIR^2}{2R^3}=\frac{\mu_oI}{2R}$

R is the radius of the circular loop and its values is:

$R=\sqrt{\frac{A}{\pi}}=\sqrt{\frac{0.5m^2}{\pi}}=0.39m$

Then, you replace in the equation for B with mu_o = 4\pi*10^-7 T/A:

$B=\frac{(4\pi*10^{-7}T/A)(5A)}{2(0.39m)}=8.05*10^{-6}T=8.05\mu T$

and the density of the magnetic flux is

$\beta=B=8.05\mu T$

4 0

4 years ago

An athelete swims from northend to southend of a 50.0m pool in 20.0s and makes the return trip to the starting position in 22.0s

Sauron [17]

Average velocity =

(distance between start-point and end-point) / (time from start to end)
in the direction of
(direction from the start-point to the end-point) .

a). The average velocity for the first half is

   (50m)/(20sec) = 2.5 m/s south.

b). The average velocity for the second half is

      (50m)/(22sec) = 2.273 m/s north

c). Average velocity for the round trip is zero, because
the start-point and end-point are the same point.

However ...

Average SPEED = (total distance covered) / (time to cover the distance)

Average SPEED for the round trip is

   (100 m) / (42 sec) = 2.381 m/s (rounded)

4 0

3 years ago

A falling stone is at a certain instant 90 feet above the ground. two seconds later it is only 10 feet above the ground. if it w

choli [55]

The equation relevant to this is:

S(t) = So + Vot - At²/2

Therefore we can create two equations:
S(t) = 90 = So - 4t - 16.1t² --> eqtn 1
S(t+2) = 10 = So - 4(t+2) - 16.1(t+2)² --> eqtn 2

Expanding eqtn 2:
10 = So - 4t - 8 - 16.1(t² + 4t + 4)
10 = So - 4t - 8 - 16.1t² - 64.4t - 64.4
10 + 8 + 64.4 = So - 68.4t - 16.1t²
82.4 = So - 68.4t - 16.1t² --> eqtn 3

Subtracting eqtn 1 by eqtn 3:

90 = So - 4t - 16.1t²

82.4 = So - 68.4t - 16.1t²

=> 7.6 = 64.4t

t = 0.118 s

Therefore calculating for initial height So:

82.4 = So - 68.4(0.118) - 16.1(0.118)²

So = 90.7 ft

7 0

3 years ago

Calculate the pressure, in atmospheres, exerted by each of the following:

gregori [183]

Answer:

a) 14.2 atm

b) 4.46 atm

c) 1.06 atm

Explanation:

For an ideal gas,

PV = nRT

P = pressure of the gas

V = volume occupied by the gas

n = number of moles of the gas

R = molar gas constant = 0.08206 L.atm/mol.K

T = temperature of the gas in Kelvin

a) For HF,

P =?, V = 2.5L, n = 1.35 moles, T = 320K

P = 1.35 × 0.08206 × 320/2.5

P = 14.2 atm

b) For NO₂

P =?, V = 4.75L, n = 0.86 moles, T = 300K

P = 0.86 × 0.08206 × 300/4.75

P = 4.46 atm

c) For CO₂

P =?, V = 5.5 × 10⁴ mL = 55L, n = 2.15 moles, T = 57°C = 330K

P = 2.15 × 0.08206 × 330/55

P = 1.06 atm

4 0

4 years ago