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3 years ago

Can you answer this ASAPPPPP HELPPPP

Physics

1 answer:

stira [4]3 years ago

7 0

The unknown sample is a mixture of Gas-Y and Gas-Z.

The unknown sample has all of the lines from the Y spectrum and the Z spectrum, and none of the lines that are only in the W or the X spectrum.

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Liquids usually have higher volume coefficients of expansion than solids do. true or false

Ulleksa [173]

Answer: true

Explanation:

5 0

3 years ago

Read 2 more answers

You place the spring vertically with one end on the floor. You then lay a 1.60 kg book on top of the spring and release the book

malfutka [58]

Answer:

Compression in the spring, x = 3.7 cm

Explanation:

It is given that,

Mass of the book, m = 1.6 kg

It can be assumed the spring constant of the spring is, k = 840 N/m

As the book moves down, the change in potential energy of the book is converted to spring potential energy of compression. The mathematical expression is as follows :

$\dfrac{1}{2}kx^2=mgx$

$x=\dfrac{2mg}{k}$

$x=\dfrac{2\times 1.6\ kg\times 9.8\ m/s^2}{840\ N/m}$

x = 0.037 meters

x = 3.7 cm

So, the spring is compressed to a distance of 3.7 cm. Hence, this is the required solution.

4 0

3 years ago

If a 20 g cannonball is shot from a 5 kg cannon with a velocity of 100

balu736 [363]

Strange as it may seem, the statement in the question appears to be TRUE.

-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.

-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.

-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)

-- Momentum = (mass) x (velocity)

After the shot, the momentum of the cannonball is

(0.02 kg) x (100 m/s ==> that way)

Momentum of the ball = 2 kg-m/s ==> that way.

-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .

Momentum of cannon = (5 kg) x (V m/s this way <==)

2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)

Divide each side by (5 kg):

V m/s = (2/5) m/s this way <==

Speed of recoil of the cannon = -- 0.4 m/s

3 0

3 years ago

If the mass of a 1.8 g paperclip was able to be completely converted to energy, how much energy would you obtain?

Anton [14]

Answer:

$E=1.62\times 10^{14}\ J$

Explanation:

Given that,

The mass of the paperclip, m = 1.8 g = 0.0018 kg

We need to find the energy obtained. The relation between mass and energy is given by :

$E=mc^2$

Where

c is the speed of light

So,

$E=0.0018\times (3\times 10^8)^2\\\\E=1.62\times 10^{14}\ J$

So, the energy obtained is $1.62\times 10^{14}\ J$ .

7 0

3 years ago

Why do liquids solidefy?

Setler79 [48]

energy extracted out of liquids an atoms are left to come closer arrange themselves shorter distance and then they solidify

4 0

3 years ago