Answer:
C
Step-by-step explanation:
It is between three and four.
*n wil have three distinct elements when exactly two of the elements (n-2, n+2, 2n, n/2) are the same.
If n-2=n+2:
![n-2=n+2 \\ n-n=2+2 \\ 0=4 \\ \hbox{no solutions}](https://tex.z-dn.net/?f=n-2%3Dn%2B2%20%5C%5C%0An-n%3D2%2B2%20%5C%5C%0A0%3D4%20%5C%5C%0A%5Chbox%7Bno%20solutions%7D)
If n-2=2n:
![n-2=2n \\ -2=2n-n \\ n=-2](https://tex.z-dn.net/?f=n-2%3D2n%20%5C%5C%0A-2%3D2n-n%20%5C%5C%0An%3D-2)
If n-2=n/2:
![n-2=\frac{n}{2} \\ 2(n-2)=n \\ 2n-4=n \\ 2n-n=4 \\ n=4](https://tex.z-dn.net/?f=n-2%3D%5Cfrac%7Bn%7D%7B2%7D%20%5C%5C%0A2%28n-2%29%3Dn%20%5C%5C%0A2n-4%3Dn%20%5C%5C%0A2n-n%3D4%20%5C%5C%0An%3D4)
If n+2=2n:
![n+2=2n \\ 2=2n-n \\ n=2](https://tex.z-dn.net/?f=n%2B2%3D2n%20%5C%5C%0A2%3D2n-n%20%5C%5C%0An%3D2)
If n+2=n/2:
![n+2=\frac{n}{2} \\ 2(n+2)=n \\ 2n+4=n \\ 2n-n=-4 \\ n=-4](https://tex.z-dn.net/?f=n%2B2%3D%5Cfrac%7Bn%7D%7B2%7D%20%5C%5C%0A2%28n%2B2%29%3Dn%20%5C%5C%0A2n%2B4%3Dn%20%5C%5C%0A2n-n%3D-4%20%5C%5C%0An%3D-4)
If 2n=n/2:
![2n=\frac{n}{2} \\ 2 \times 2n=n \\ 4n=n \\ 4n-n=0 \\ 3n=0 \\ n=0](https://tex.z-dn.net/?f=2n%3D%5Cfrac%7Bn%7D%7B2%7D%20%5C%5C%0A2%20%5Ctimes%202n%3Dn%20%5C%5C%0A4n%3Dn%20%5C%5C%0A4n-n%3D0%20%5C%5C%0A3n%3D0%20%5C%5C%0An%3D0)
*n have exactly three distinct elements for 5 distinct integers n.
*(-4)={-8, -6, -2}
*(-2)={-4, -2, -1}
*0={-2, 0, 2}
*2={0, 1, 4}
*4={2, 6, 8}
Here, We have to find distance travelled by the car at the speed of 40km/h in 11.5 hours...~
![\sf \: distance = speed \times time](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20distance%20%3D%20speed%20%5Ctimes%20time)
![\tt \: distance = 40 \times 11.5](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%20distance%20%3D%2040%20%5Ctimes%2011.5)
![\tt \: distance = 460 \: km](https://tex.z-dn.net/?f=%20%5Ctt%20%5C%3A%20distance%20%3D%20460%20%5C%3A%20km)
<em>Thus, The car will travel 460 km in 11.5 hours at the speed of 40km/h...</em>
plug in your values into
I = PRT
480 = P(.04)(6)
solve for P
check your answer by finding the interest.