If we assume the hypotenuse is of side length 5:
a^2+b^2=c^2
3^2+b^2=5^2
9+b^2=25
b^2=16
b=4
If the hypotenuse is the unknown:
a^2+b^2=c^2
3^2+5^2=c^2
9+25=c^2
c^2=34
c=(34)^(1/2)
Answer:
its b because when subtract 30-24=6
Answer:
Number of senior citizen tickets sold= 110
Number of adults tickets sold= 290
Step-by-step explanation:
<u>First, we need to establish a system of equations:</u>
x= number of adults tickets
y= number of senior citizen tickets
x + y= 400
6x + 3y= 2,070
<u>Now, we isolate x in one equation and substitute the value in the other:</u>
x= 400 - y
6*(400 - y) + 3y = 2,070
2,400 - 6y + 3y = 2,070
330 = 3y
110 = y
Number of senior citizen tickets sold= 110
Number of adults tickets sold= 290
<u>Prove:</u>
290 + 110= 400
6*290 + 3*110= 2,070
Answer:here use
Step-by-step explanation:
To graph y = f (x-h), move the graph of h units to the right. We have then: g (x) = (x-2) ^ 2 ... If mEB=72 and the mB D 3y - 27, then<br /> y =.
