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Dmitrij [34]
3 years ago
11

For the fair,the organizers ordered 32 rolls of tickets.Each roll of tickets has 100 tickets. How many tickets were ordered in a

ll?
Mathematics
1 answer:
creativ13 [48]3 years ago
7 0
You take 32 times 100 and that gets you 3,200 tickets
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anygoal [31]
<span>4</span>\frac{188}{231}
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2 years ago
I WILL GIVE YOU BRAINLIEST PLEASE HELPPPPP
Vanyuwa [196]

Answer: 3/2

Step-by-step explanation:

Let's consider the points (6,9) and (4,6).

The difference in the y coordinates is 3, and the diffeence in the x coordinates is 2.

So, the slope is 3/2.

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2 years ago
Use integration by parts to derive the following formula from the table of integrals.
emmasim [6.3K]

Answer:

I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)

Step-by-step explanation:

for

I= ∫x^n . e^ax dx

then using integration by parts we can define u and dv such that

I= ∫(x^n) . (e^ax dx) = ∫u . dv

where

u= x^n → du = n*x^(n-1) dx

dv= e^ax  dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)

then we know that

I= ∫u . dv = u*v - ∫v . du + C

( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =

(u*v) - ∫v*du + C )

therefore

I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C

I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)

5 0
2 years ago
How can the statement below be rewritten as a conditional statement in if-then form?
Irina-Kira [14]

Answer:

<h2>If two angles measures 180 degrees, then they form a linear pair.</h2>

Step-by-step explanation:

The conditional statement should be this way, because after the word ''if'', should be placed the condition, and after the word ''then'', should be the consequence.

5 0
3 years ago
the graph of f(x) is shown below. what are the values of a, b, c, and d in the definition of f(x) below? (graph and definition o
Otrada [13]

Answer:

Step-by-step explanation:

For the given piecewise function,

Let the equation of the segment AB is,

y = ax + 7 where x < -2

Since a point (-2, 3) lies on the given line,

3 = a(-2) + 7

3 - 7 = -2a

a = 2

Therefore, f(x) = 2x + 7 when x < -2

For the segment BC,

f(x) = 3 where -2 ≤ x ≤ 2

For the segment CD,

f(x) = bx + 9

Since a point (2, 3) lies on this segment,

f(2) = 2b + 9 = 3

2b = 3 - 9

b = -3

Therefore, equation of segment CD will be,

f(x) = (-3)x + 9   where x > 2

7 0
2 years ago
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