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3 years ago

In metallic bonding, the electrons

2 answers:

6 0

A metallic bond is a bond between two metals or cations. In metallic bonding, the electrons are shared between the positive ions. The electrons move around between atoms. This is what allows objects with metallic bonds to be malleable and able to conduct electricity.

Ivan3 years ago

6 0

Answer:

In metallic bonds the electrons of the valence shell can move freely within the metal, thus explaining its electric conductivity.

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H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.06×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.18×10−19, what is the equilibrium constant Kfinal for

serg [7]

Answer:

Therefore the equilibrium constant $K_{final}$ is 9.35× 10²⁵

Explanation:

Equilibrium constant:

Equilibrium constant is used to find out the ratio of the concentration of the product to that of reactant.

xA+yB→zC

The equilibrium constant K,

$k=\frac{[C]^z}{[A]^x[B]^y}$

Here [A] is equilibrium concentration of A

[B] is equilibrium concentration of B

[C] is equilibrium concentration of C.

1. $H_2S(aq)\rightleftharpoons HS^-(aq)+H^+(aq)$ $K_1= 9.06 \times 10^{-8}$

$K_1=\frac{[HS^-][H^+]}{[H_2S]}$

2. $HS^-(aq)\rightleftharpoons S^{2-}(aq)+H^+(aq)$ $K_2= 1.18 \times 10^{-19}$

$K_2=\frac{[S^{2-}][H^+]}{[HS^-]}$

$S^{2-}(aq)+2H^+(aq)\rightleftharpoons H_2S(aq)$

$K_3=\frac{[H_2S]}{[S^{2-}][H^+]^2}$

Therefore,

$k_1k_2=\frac{[HS^-][H^+]}{[H_2S]}\frac{[S^{2-}][H^+]}{[HS^-]}$

$\Rightarrow k_1k_2=\frac{[S^{2-}][H^+]^2}{[H_2S]}$

$\Rightarrow k_1k_2=\frac{1}{K_3}$

$\Rightarrow K_3=\frac{1}{K_1K_2}$

$\Rightarrow K_3=\frac{1}{9.06\times 10^{-8}\times 1.18\times 10^{-19}}$

⇒K₃=9.35× 10²⁵

$K_3=K_{final}$

Therefore the equilibrium constant $K_{final}$ is 9.35× 10²⁵

3 0

3 years ago

ii. If the pressure after landing was 1.0 atm, what was the volume of the passenger's collapsed water bottle? (Assume the bottle

Anon25 [30]

Using the ideal gas equation and Gay Lussac's law, the volume of the passenger's collapsed bottle after landing is 0.0075 L.

<h3>What is ideal gas equation?</h3>

The ideal gas equation shows the relationship between temperature, pressure, volume and number of moles.

The volume of the passenger's collapsed bottle after landing is 0.0075 L.

Given that;

PV = nRT

P = gas pressure
V = volume of gas
n = number of moles of gas
R = molar gas constant
T = temperature

n = PV/RT

Hence:

P = 0.75 atm;

V = 0.5 L;

T = 295 K;

R = 0.082 atmL/K.mol

n = 0.75 * 0.5 / 0.082 * 295

n = 0.015 moles

If the pressure after landing was 1.0 atm;

V1n1 = V2n2

V2= V1n1/n2

V2 = 0.5 L * 0.015 moles/ 1 mole

V2 = 0.0075 L

The volume of the passenger's collapsed bottle after landing is 0.0075 L.

Missing parts;

A passenger on an airplane finished a 0.5 L bottle of water during the flight

and replaced the lid. The cabin pressure and temperature were maintained at

0.75 atm and 295 K during the flight. After landing, he noticed his empty water

bottle had collapsed. (12 points)

i. How many moles of gas were in the water bottle?

Learn more about ideal gas equation: brainly.com/question/4147359

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4 0

2 years ago

Thinking and questioning is the start of the scientific inquiry process

Lelu [443]

Explanation:The scientific inquiry process is the process in which scientists or researchers find an explanation for any natural world phenomena with logic and evidence collected by the systemic method or work. The scientific inquiry process begins with a question or thinking (observation) for any natural phenomena like why freshwater has low albedo where ice has a high albedo percentage.

3 0

3 years ago

5.690x10^3 miles to meters and give sig figs<br>Please help!

Veseljchak [2.6K]

The equivalent of 5.690 × 10³ miles in metres is 9157167 metres. Details about metres and miles can be found below.

<h3>How to convert miles to metres?</h3>

Miles and metres are both units for measuring distance between two bodies or locations.

However, they can be converted interchangeably as follows:

1 mile = 1609.34 metres

According to this question, 5.690 × 10³ miles can be converted to metres as follows;

5.690 × 10³ × 1609.34 = 9157167 metres.

Therefore, the equivalent of 5.690 × 10³ miles in metres is 9157167 metres.

Learn more about miles and metres at: brainly.com/question/20822566

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4 0

2 years ago

Calculate the energy of an electron that emits light at a wavelength of 5.00 x 10^-7m.

Anni [7]

Answer:

The energy of electron is 3.978×10⁻¹⁹ j.

Explanation:

Given data:

Energy of electron = ?

Wavelength of electron = 5.00 ×10⁻⁷ m

Solution:

Formula:

E = hc/λ

E = energy

h = planck's constant (6.63×10⁻³⁴ j.s)

c = speed of light

λ = wavelength

Now we will put the values in formula.

E = 6.63×10⁻³⁴ j.s × 3×10⁸ m/s / 5.00 ×10⁻⁷ m

E = 19.89×10⁻²⁶ j.m /5.00 ×10⁻⁷ m

E = 3.978×10⁻¹⁹ j

The energy of electron is 3.978×10⁻¹⁹ j.

3 0

3 years ago