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fredd [130]
3 years ago
12

Calculate the energy of an electron that emits light at a wavelength of 5.00 x 10^-7m.

Chemistry
1 answer:
Anni [7]3 years ago
3 0

Answer:

The energy of electron is 3.978×10⁻¹⁹ j.

Explanation:

Given data:

Energy of electron = ?

Wavelength of electron = 5.00 ×10⁻⁷ m

Solution:

Formula:

E = hc/λ

E = energy

h = planck's constant (6.63×10⁻³⁴ j.s)

c = speed of light

λ = wavelength

Now we will put the values in formula.

E = 6.63×10⁻³⁴ j.s × 3×10⁸ m/s / 5.00 ×10⁻⁷ m

E = 19.89×10⁻²⁶ j.m /5.00 ×10⁻⁷ m

E = 3.978×10⁻¹⁹ j

The energy of electron is 3.978×10⁻¹⁹ j.

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6 C(s) + 3 H2(g) → 2 C6H6(l) Δ H = 49 kJ<br><br> TRUE or FALSE
VMariaS [17]

Answer:

True => ΔH°f for C₆H₆ = 49 Kj/mole

Explanation:

See Thermodynamic Properties Table in appendix of most college level general chemistry texts. The values shown are for the standard heat of formation of substances at 25°C. The Standard Heat of Formation of a substance - by definition - is the amount of heat energy gained or lost on formation of the substance from its basic elements in their standard state. C₆H₆(l) is formed from Carbon and Hydrogen in their basic standard states. All elements in their basic standard states have ΔH°f values equal to zero Kj/mole.

7 0
4 years ago
What would happen to a diver who does no exhale while surfacing from a 30 m dive?
sertanlavr [38]
Their lungs would try to expand to about 4 timed the normal volume which would force air into the various body tissues. this can cause a lung expansion injury and it could case air embolism. Air embolism is when air bubbles get trapped in blood vessels. This can lead to a blockage which will could be fatal.
6 0
4 years ago
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
Which of the following uses light energy to convert co2 and h2o to organic compounds?
Dimas [21]
Photosynthesis is where carbon dioxide and water through light energy is converted in glucose and other organic compounds.
4 0
3 years ago
What will happen to the pH of a buffer if acid/base ratio is increased by 100?
sp2606 [1]

Answer:

It will decrease by 2 units.

Explanation:

The Henderson-Hasselbalch equation for a buffer is

pH = pKa + log(base/acid)

Let's assume your acid has pKa = 5.

(a) If the base: acid ratio is 1:1,

pH(1) = 5 + log(1/1) = 5  + log(1) = 5 + 0 = 5

(b) If the base: acid ratio is 1:100,

pH(2) = 5 + log(1/100) = 5  + log(0.01) = 5 - 2 = 3

(c) Difference

ΔpH = pH(2) - pH(1) = 5 - 3 = -2

If you increase the acid:base ratio to 100:1, the pH will decrease by two units.

4 0
3 years ago
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