Answer:
Average atomic mass = 21.38 amu.
Explanation:
Given data:
Mass of first isotope = 21 amu
Abundance of first isotope = 62%
Mass of second isotope = 22 amu
Abundance of second isotope = 38%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (62×21)+(38×22) /100
Average atomic mass = 1302 +836 / 100
Average atomic mass = 2138 / 100
Average atomic mass = 21.38 amu.
Answer: its B: I, II, III, and IV
Explanation: i took the K12 test
Complementary pairing goes like this:
A pairs with T and
C pairs with G. Nothing about this changes unless you get to mRNA (But we won't go into that) :)
So if you have a strand that goes TCG GA then your pairing will look like this:
T A
C G
G C
G C
A T
Hope this helps!! :)
Answer:
did you delete it or no? because that might've happened
Explanation:
it happened to me once
Answer:
-Physical properties possessed by all stars:
- They are made of gases such as hydrogen and helium.
- They shine very brightly due to interaction of hydrogen and helium at appropriate pressure and temperature.
- They contain iron in their cores which monitors the fusion reaction.
- They make energy through fusion between the gases present in the stars which are hydrogen and helium.
- They are not spherical in shape hence this physical property is false in terms physical properties of the stars.
Hope this helps. If it does, please mark me brainliest.
Explanation:
