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stellarik [79]
3 years ago
12

Make q the subject of the formula

Bq%7D%20%3D%20c" id="TexFormula1" title=" \frac{a}{p } - \frac{b}{q} = c" alt=" \frac{a}{p } - \frac{b}{q} = c" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

q=<u>bp</u>

<u> </u><u> </u><u> </u><u> </u>a- cp

Step-by-step explanation:

<u>a</u> - <u>b</u><u> </u>= c

p q

Multiply through by pq

qa - bp = cpq

qa - cpq = bp

q [a-cq] = bp

q= <u>bp</u>

<u> </u><u> </u><u> </u><u> </u><u> </u>a-cp

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What is the equation of the line represented by the table of values?
vredina [299]

Answer: (C) y= x − 2

Explanation:

y=x-2 is the choice that satisfies all the points in the table. This can be verified case by case:

y=x-2

(-3,-5): -5 = -3 -3

(-1,-3): -3 = -1 - 2

(1,-1): -1 = 1 - 2

(3, 1): 1 = x - 2

(5,3): 3 = 5 - 3


5 0
3 years ago
CAN SOMEONE HELP WITH THIS ASAP
Iteru [2.4K]
The answer to this question is D.
6 0
3 years ago
Mr. Bernstein owns 11 paintings, but has only enough wall space in his home to display five of
SpyIntel [72]

Answer:

In algebra, we often study relationships where a change to one variable causes change in another variable. Describe a situation you’re familiar with where one quantity changes constantly in relation to another quantity. How are the two quantities in the situation related? If you represent the two quantities on a graph, what will it look like?

Step-by-step explanation:

4 0
3 years ago
Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



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What is 2^10 divided by 5
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1024/5

204.8

that's it
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