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Alja [10]
3 years ago
11

Which equation represents the volume of a cone with the same base and height as the cylinder below? A cylinder with a height k a

nd radius t. Volume cone = pi t squared k Volume cone = one-third pi t squared k Volume cone = one-half pi t squared k Volume cone = 3 pi t squared k
Mathematics
2 answers:
DerKrebs [107]3 years ago
5 0

Answer:

The correct answer is Volume Cone = one-third pi t squared k

Step-by-step explanation:

Igoryamba3 years ago
3 0

Answer: The correct answer is Volume Cone = one-third pi t squared k

Step-by-step explanation: The first important detail to note here is that both cylinder and cone have the same base and the same height This implies that when writing out the formula for calculating the volume of either of the two shapes, the radius and the height will be the same number or value.

The volume of a cylinder is given as;

Volume cylinder = pi x r squared x h (that is πr²h)

Also the volume of a cone is given as;

Volume cone = one-third x pi x r squared x h (that is 1/3*πr²h)

However, the variables have been changed such that the radius r is now represented by t while the height h is now represented by k.

Therefore the volume of the cone should now be re-written as;

Volume cone = one-third pi t squared k <em>(that is 1/3 *πt²k)</em>

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Determine the inverse of the function f (x) = 4(x − 3)2 + 2. inverse of f of x is equal to 3 minus the square root of the quanti
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The inverse of the function f(x)  = 4(x-3)² + 2 is f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

The given function is:

f(x)   =  4(x  - 3)²  +  2

To find the inverse of the function:

Make x as the subject of the formula

4(x-3)^2 = f(x) - 2\\(x-3)^2 = \frac{f(x)-2}{4} \\x - 3 = \sqrt{\frac{f(x)-2}{4} } \\x = \sqrt{\frac{f(x)-2}{4} } + 3

Replace x by f^{-1}(x) and replace f(x) by x

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Therefore, the inverse of the function is:

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Learn more here: brainly.com/question/17285960

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Step-by-step explanation:

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