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2 years ago

14 and 11/12 + 3 and 1/6

1 answer:

8 0

let's firstly convert the mixed fractions to improper fractions and then add them up, bearing in mind that the LCD from 12 and 6 will just be 12.

$\bf \stackrel{mixed}{14\frac{11}{12}}\implies \cfrac{14\cdot 12+11}{12}\implies \stackrel{improper}{\cfrac{179}{12}}~\hfill \stackrel{mixed}{3\frac{1}{6}}\implies \cfrac{3\cdot 6+1}{6}\stackrel{improper}{\cfrac{19}{6}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{179}{12}+\cfrac{19}{6}\implies \stackrel{\textit{using the LCD of 12}}{\cfrac{(1)179~~+~~(2)19}{12}}\implies \cfrac{179+38}{12}\implies \cfrac{217}{12}\implies 18\frac{1}{12}$

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Slav-nsk [51]

Answer:

198 is the variance for the number of defective parts made each week.

Step-by-step explanation:

We are given the following in the question:

Number of parts produced each week = 20,000

Percentage of defective parts = 1%

We have to calculate the variance for the number of defective parts made each week.

We treat defective part as a success.

P(Defective part) = 1% = 0.01

$p = 0.01$

Then the number defective parts follows a binomial distribution .

Formula for variance =

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Thus, 198 is the variance for the number of defective parts made each week.

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3 years ago

Help! Geometry Triangle Congruence

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Answer:

Step-by-step explanation:

Thank your for revising and improving the image.

Assuming DF is a straight line,

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CE || GF

Then

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2 years ago

Several mountain climbers move up a mountain

Dimas [21]

Answer:

2 5/8

Step-by-step explanation:

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3 years ago

There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter

Goshia [24]

Answer:

The question is incomplete, this is the complete question.;

There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter.find the probability of this occurring.

The answer to the question is;

the probability of this occurring is 1/27

Step-by-step explanation:

Let n(N) =5 ( the number of nickels)

n(D) =5 ( the number of dimes) and

n(Q) = 5 ( the number of quarters)

P(N)= 5/15=1/3 (prob of picking a nickel)

P(D) =5/15=1/3 (prob of picking a dime)

P(Q) = 5/15= 1/3 (prob of picking a quatre)

The probability of picking the three= P(N)×P(D)×P(Q)

= 1/3×1/3×1/3

= 1/27

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3 years ago